Math Problem Statement
Solution
The question asks about optimizing production to maximize profit, and this can be framed as a linear programming problem. Let's break down the setup.
Problem Summary:
-
T50 DVD Player:
- Uses 4 ounces of plastic
- Uses 4 ounces of metal
- Profit: $10 per unit
- Max units: 20 units per week
-
G150 DVD Player:
- Uses 2 ounces of plastic
- Uses 8 ounces of metal
- Profit: $18 per unit
-
Available materials:
- 164 ounces of plastic
- 464 ounces of metal
Goal:
Maximize profit by determining how many units of T50 and G150 should be produced, subject to material and production constraints.
Variables:
- Let = number of T50 units
- Let = number of G150 units
Constraints:
-
Plastic Constraint:
(Total plastic used) -
Metal Constraint:
(Total metal used) -
Production Limit for T50:
-
Non-negativity:
,
Objective Function:
Maximize profit:
Solution Approach:
We will solve this using linear programming to find the values of and that maximize the profit while satisfying the constraints.
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Math Problem Analysis
Mathematical Concepts
Linear Programming
Optimization
Algebra
Formulas
Plastic constraint: 4x + 2y ≤ 164
Metal constraint: 4x + 8y ≤ 464
Production limit for T50: x ≤ 20
Profit function: 10x + 18y
Theorems
Linear Programming Theorem
Suitable Grade Level
Grades 11-12, College Level
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