Math Problem Statement
the sum of a number squared and a second number is 27. What are their values if you want to maximize their product
Solution
We are given the following information:
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The sum of the square of one number and a second number is 27. This translates to the equation: where is the first number and is the second number.
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We want to maximize the product of these two numbers, .
Step 1: Express in terms of
From the equation , solve for :
Step 2: Write the product function
Now substitute into the product function : This is the function we want to maximize.
Step 3: Find the critical points by taking the derivative
To maximize , we first find its derivative with respect to :
Set the derivative equal to zero to find the critical points:
Step 4: Determine which critical point maximizes the product
We now check the second derivative to determine whether these points correspond to a maximum or minimum: For , we have: For , we have:
Thus, the value gives a maximum.
Step 5: Find
When , substitute into the equation :
Conclusion
The values of the two numbers that maximize the product are and . The maximum product is:
Do you need any further details or clarifications?
Here are some additional questions you might find interesting:
- How would the product change if we modified the sum condition to something different, like 30 instead of 27?
- Can the product be maximized for negative values of ?
- What would the product be if we tried maximizing the sum of the two numbers instead of their product?
- How does the solution change if we restrict and to integer values only?
- How could we graph the function to visualize the maximum point?
Tip: Always check the second derivative to confirm whether a critical point corresponds to a maximum or a minimum.
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Math Problem Analysis
Mathematical Concepts
Algebra
Optimization
Derivative Calculus
Formulas
x^2 + y = 27
P = x * y
Derivative of P(x): dP/dx = 27 - 3x^2
Second derivative test: d^2P/dx^2 = -6x
Theorems
First derivative test for critical points
Second derivative test for concavity
Suitable Grade Level
Grades 11-12
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