Math Problem Statement

You have 120 feet of wire to enclose 2 sides of a garden. Two sides are against walls so they need no fence.

The vertical side (labeled x) requires 4 strands of wire.

The horizontal side (labeled y) requires 5 strands of wire.

What values for x and y will create a fence that encloses the maximum area of garden?

x =

y =

Enter each answer as a whole number or as

a reduced fraction (such as 4/5, 35/4 or 11/2).

Solution

To solve this problem, we will first define the variables and write the constraints based on the given information.

Step 1: Defining Variables

  • xx: The length of the vertical side of the garden (along the wall).
  • yy: The length of the horizontal side of the garden (perpendicular to the wall).

The total amount of wire is 120 feet. Since the vertical side needs 4 strands of wire and the horizontal side needs 5 strands, we can write an equation for the total wire used:

4x+5y=1204x + 5y = 120

Step 2: Objective Function

We want to maximize the area of the garden, which is given by:

A=xyA = x \cdot y

Step 3: Solve for One Variable in Terms of the Other

We can express yy in terms of xx using the constraint equation:

5y=1204x5y = 120 - 4x y=1204x5y = \frac{120 - 4x}{5}

Step 4: Substituting into the Area Formula

Substitute the expression for yy into the area formula:

A=x(1204x5)A = x \cdot \left( \frac{120 - 4x}{5} \right) A=x(1204x)5A = \frac{x(120 - 4x)}{5} A=120x4x25A = \frac{120x - 4x^2}{5}

Step 5: Maximizing the Area

To maximize the area, we will take the derivative of AA with respect to xx and set it equal to zero.

dAdx=ddx(120x4x25)\frac{dA}{dx} = \frac{d}{dx} \left( \frac{120x - 4x^2}{5} \right) dAdx=1208x5\frac{dA}{dx} = \frac{120 - 8x}{5}

Set the derivative equal to zero to find the critical points:

1208x5=0\frac{120 - 8x}{5} = 0 1208x=0120 - 8x = 0 8x=1208x = 120 x=15x = 15

Step 6: Find yy

Now substitute x=15x = 15 back into the equation for yy:

y=1204(15)5y = \frac{120 - 4(15)}{5} y=120605y = \frac{120 - 60}{5} y=605y = \frac{60}{5} y=12y = 12

Final Answer

The values of xx and yy that maximize the area are:

x=15andy=12x = 15 \quad \text{and} \quad y = 12

These dimensions will enclose the maximum area.


Would you like further details on how to approach similar problems or any clarifications on this one? Here are some related questions to explore:

  1. How can you generalize this type of optimization problem for other shapes (e.g., circular or triangular fences)?
  2. What is the significance of the second derivative in confirming the maximum area?
  3. How would the solution change if the amount of wire were different?
  4. How does the number of strands for each side affect the final dimensions?
  5. How can this approach be used in real-life scenarios, like fencing a garden or property?

Tip: When solving optimization problems with constraints, always start by expressing the constraint in terms of one variable and substitute it into the objective function before differentiating.

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Math Problem Analysis

Mathematical Concepts

Optimization
Algebra
Maximizing Area
Derivatives

Formulas

Area = x * y
4x + 5y = 120
Derivative of A = (120 - 8x) / 5

Theorems

Optimization using derivatives
Critical points for maximum/minimum

Suitable Grade Level

Grades 9-12