Math Problem Statement

A candy company has 138 kg of chocolate-covered nuts and 78 kg of chocolate-covered raisins to be sold as two different mixes. One mix will contain half nuts and half raisins and will sell for $7 per kg. The other mix will contain ¾ nuts and ¼ raisins and will sell for $9.50 per kg. How many kilograms of each mix should the company prepare for maximum revenue?

Solution

Let's break down the problem step by step.

Part (a):

The company has 138 kg of chocolate-covered nuts and 78 kg of chocolate-covered raisins. The products will be sold in two different mixes:

  • Mix 1 contains half nuts and half raisins, and sells for $7 per kg.
  • Mix 2 contains 34\frac{3}{4} nuts and 14\frac{1}{4} raisins, and sells for $9.50 per kg.

The company needs to decide how many kilograms of each mix to prepare in order to maximize revenue.

Let:

  • x1x_1 be the kilograms of Mix 1.
  • x2x_2 be the kilograms of Mix 2.

Each mix uses up the nuts and raisins according to its recipe, and the constraints are:

  • Nuts constraint: 12x1+34x2138\frac{1}{2}x_1 + \frac{3}{4}x_2 \leq 138 (from the total amount of nuts available).
  • Raisins constraint: 12x1+14x278\frac{1}{2}x_1 + \frac{1}{4}x_2 \leq 78 (from the total amount of raisins available).

The objective is to maximize the revenue, which is given by: Revenue=7x1+9.5x2\text{Revenue} = 7x_1 + 9.5x_2

We solve this linear programming problem to determine the values of x1x_1 and x2x_2.

Part (b):

Now, the price of Mix 2 is raised to $11 per kg. The revenue equation becomes: Revenue=7x1+11x2\text{Revenue} = 7x_1 + 11x_2 The same constraints apply. We solve this revised problem to find the new optimal amounts of Mix 1 and Mix 2, and the maximum revenue.

I'll calculate the values using the appropriate method.### Results:

Part (a):

  • The company should prepare 96 kg of Mix 1 and 120 kg of Mix 2.
  • The maximum revenue will be $1812.

Part (b):

  • After the price increase for Mix 2, the company should prepare 0 kg of Mix 1 and 184 kg of Mix 2.
  • The maximum revenue will be $2024.

Would you like any more details or clarification?

Follow-up Questions:

  1. How are the constraints for the nuts and raisins derived?
  2. Why does the price change in Mix 2 affect the preparation amounts so drastically?
  3. How would the solution change if the price of Mix 1 increased?
  4. What other techniques could be used to solve this optimization problem?
  5. Can you explain how the linear programming method finds the optimal solution?

Tip:

When dealing with multiple products and limited resources, adjusting prices can dramatically shift production strategies to maximize revenue.

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Optimization
Revenue Maximization
Resource Allocation

Formulas

Revenue = 7x₁ + 9.5x₂ (initial) or Revenue = 7x₁ + 11x₂ (after price increase)
Nuts constraint: ½x₁ + ¾x₂ ≤ 138
Raisins constraint: ½x₁ + ¼x₂ ≤ 78

Theorems

Linear Programming Optimization
Simplex Method (optional)

Suitable Grade Level

Grades 10-12