Math Problem Statement

The back of Dante's property is a creek. Dante would like to enclose a rectangular area, using the creek as one side and fencing for the other three sides, to create a corral. If there is 200 feet of fencing available, what is the maximum possible area of the corral?

Solution

To solve this problem, we need to maximize the area of a rectangular corral with three sides fenced, using the creek as the fourth side. Let's define the variables and set up the equations:

  1. Variables:

    • xx: the length of the side perpendicular to the creek.
    • yy: the length of the side parallel to the creek.
  2. Fencing constraint: Since the creek acts as one side, the fencing is only needed for the three other sides (two sides of length xx and one side of length yy). The total amount of fencing available is 200 feet, so we have: 2x+y=2002x + y = 200

  3. Area of the corral: The area AA of the corral is given by: A=x×yA = x \times y

To find the maximum possible area, we need to express AA in terms of a single variable. Let's solve for yy from the fencing constraint:

y=2002xy = 200 - 2x

Substitute yy into the area formula:

A(x)=x(2002x)A(x) = x(200 - 2x)

Simplify this equation:

A(x)=200x2x2A(x) = 200x - 2x^2

Now, we have a quadratic function A(x)=2x2+200xA(x) = -2x^2 + 200x. This quadratic function opens downwards (since the coefficient of x2x^2 is negative), so its maximum value occurs at its vertex.

The x-coordinate of the vertex of a quadratic function ax2+bx+cax^2 + bx + c is given by:

x=b2ax = -\frac{b}{2a}

For our function, a=2a = -2 and b=200b = 200:

x=2002(2)=2004=50x = -\frac{200}{2(-2)} = \frac{200}{4} = 50

Now, substitute x=50x = 50 back into the equation for yy:

y=2002(50)=200100=100y = 200 - 2(50) = 200 - 100 = 100

Thus, the dimensions that maximize the area are x=50x = 50 feet and y=100y = 100 feet.

Finally, the maximum possible area AA is:

A=x×y=50×100=5000 square feetA = x \times y = 50 \times 100 = 5000 \text{ square feet}

Conclusion

The maximum possible area of the corral that Dante can enclose with 200 feet of fencing, using the creek as one side, is 5000 square feet.

Would you like more details on any part of the solution, or do you have any other questions?

Related Questions:

  1. How would the area change if the amount of fencing available were 250 feet?
  2. What if the creek is not straight but forms a semicircle around one side of the corral? How would this change the problem?
  3. How can you determine if a quadratic function opens upwards or downwards?
  4. If the fencing is unevenly distributed (e.g., different lengths for the sides perpendicular to the creek), how would you maximize the area?
  5. What is the significance of the vertex in the context of this problem?

Tip:

When dealing with optimization problems, always identify the constraints and express the quantity to be optimized in terms of a single variable to simplify the problem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Optimization

Formulas

Area of a rectangle: A = length \( \times \) width

Theorems

Quadratic functions and vertex formula

Suitable Grade Level

Grades 9-12