Math Problem Statement

Suppose A, B and C are 3 × 3 matrices such that det A = -1, det B = 4 and det C = 8. Find the determinant of the matrix [(ABC)^{-1}(4A)]^2 (C^T).

Solution

We are asked to find the determinant of the matrix expression:

[(ABC)1(4A)]2(CT),\left[(ABC)^{-1}(4A)\right]^2(C^T), where det(A)=1\det(A) = -1, det(B)=4\det(B) = 4, and det(C)=8\det(C) = 8.

Step-by-step breakdown:

1. Determinant of ABCABC:

Using the property of determinants for matrix products: det(ABC)=det(A)det(B)det(C).\det(ABC) = \det(A) \cdot \det(B) \cdot \det(C). Substitute the given values: det(ABC)=(1)48=32.\det(ABC) = (-1) \cdot 4 \cdot 8 = -32.

2. Determinant of (ABC)1(ABC)^{-1}:

The determinant of the inverse of a matrix is the reciprocal of the determinant: det((ABC)1)=1det(ABC)=132=132.\det\left((ABC)^{-1}\right) = \frac{1}{\det(ABC)} = \frac{1}{-32} = -\frac{1}{32}.

3. Determinant of 4A4A:

The determinant of a scalar multiplied by a matrix is given by: det(4A)=43det(A)=64(1)=64.\det(4A) = 4^3 \cdot \det(A) = 64 \cdot (-1) = -64. (Note: The power 3 comes from the matrix being 3×33 \times 3.)

4. Determinant of (ABC)1(4A)(ABC)^{-1}(4A):

Using the property of determinants for matrix products: det((ABC)1(4A))=det((ABC)1)det(4A).\det\left((ABC)^{-1}(4A)\right) = \det\left((ABC)^{-1}\right) \cdot \det(4A). Substitute the values: det((ABC)1(4A))=(132)(64)=2.\det\left((ABC)^{-1}(4A)\right) = \left(-\frac{1}{32}\right) \cdot (-64) = 2.

5. Determinant of [(ABC)1(4A)]2\left[(ABC)^{-1}(4A)\right]^2:

The determinant of a matrix raised to a power is the determinant raised to that power: det([(ABC)1(4A)]2)=(det((ABC)1(4A)))2=22=4.\det\left(\left[(ABC)^{-1}(4A)\right]^2\right) = \left(\det\left((ABC)^{-1}(4A)\right)\right)^2 = 2^2 = 4.

6. Determinant of CTC^T:

The determinant of a transpose of a matrix is the same as the determinant of the matrix: det(CT)=det(C)=8.\det(C^T) = \det(C) = 8.

7. Final step: Determinant of the entire expression:

Using the property of determinants for matrix products again: [ \det\left(\left[(ABC)^{-1}(4A)\right]^2(C^T)\right) = \det\left(\left[(ABC)^{-1}(4A)\right]^2\right) \cdot \det(C^T). ] Substitute the values: det([(ABC)1(4A)]2(CT))=48=32.\det\left(\left[(ABC)^{-1}(4A)\right]^2(C^T)\right) = 4 \cdot 8 = 32.

Final Answer:

32.\boxed{32}.

Let me know if you'd like any details or have further questions.

Here are 5 related questions to expand your understanding:

  1. How does the determinant change when a matrix is multiplied by a scalar?
  2. What is the relationship between the determinant of a matrix and its inverse?
  3. How do we compute the determinant of a product of matrices?
  4. What properties of transposes help in determinant calculations?
  5. Can you explain why determinants are multiplicative over matrix products?

Tip: When raising a matrix to a power, remember that the determinant of the matrix is also raised to that power.

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Math Problem Analysis

Mathematical Concepts

Matrix Determinants
Matrix Multiplication
Inverse of a Matrix
Transpose of a Matrix

Formulas

det(ABC) = det(A) * det(B) * det(C)
det((ABC)^{-1}) = 1 / det(ABC)
det(kA) = k^n * det(A) for n × n matrix
det(C^T) = det(C)
det(A^m) = (det(A))^m

Theorems

Properties of Determinants
Determinant of a Product
Determinant of an Inverse Matrix
Determinant of a Transpose Matrix

Suitable Grade Level

University level