Math Problem Statement

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mathematics problem solving

Solution

Based on the provided document, here are solutions to some of the problems extracted:

Problem 1:

Find the solution to the equation x27x+12=0x^2 - 7x + 12 = 0.

Solution: To solve the quadratic equation x27x+12=0x^2 - 7x + 12 = 0, we can factorize it.

x27x+12=(x3)(x4)=0x^2 - 7x + 12 = (x - 3)(x - 4) = 0

So, the solutions are: x=3x = 3 x=4x = 4

Problem 2:

Find the cosine of angle ACB\angle ACB for a triangle with sides AC=3AC = 3, BC=5BC = 5, and AB=7AB = 7.

Solution: Using the cosine rule: cos(ACB)=AC2+BC2AB22ACBC\cos(\angle ACB) = \frac{AC^2 + BC^2 - AB^2}{2 \cdot AC \cdot BC}

Substitute the given values: cos(ACB)=32+5272235\cos(\angle ACB) = \frac{3^2 + 5^2 - 7^2}{2 \cdot 3 \cdot 5} cos(ACB)=9+254930\cos(\angle ACB) = \frac{9 + 25 - 49}{30} cos(ACB)=1530\cos(\angle ACB) = \frac{-15}{30} cos(ACB)=0.5\cos(\angle ACB) = -0.5

Problem 3:

Find the volume of a pyramid with a base side length of 2 cm and a height of 464\sqrt{6} cm.

Solution: The volume VV of a pyramid is given by: V=13×Base Area×HeightV = \frac{1}{3} \times \text{Base Area} \times \text{Height}

The base area for a square base with side length ss is: Base Area=s2\text{Base Area} = s^2 For s=2s = 2 cm: Base Area=22=4 cm2\text{Base Area} = 2^2 = 4 \text{ cm}^2

Given height h=46h = 4\sqrt{6} cm: V=13×4×46V = \frac{1}{3} \times 4 \times 4\sqrt{6} V=1663 cm3V = \frac{16\sqrt{6}}{3} \text{ cm}^3

Problem 4:

Calculate the probability of selecting a student whose shoe size is greater than the average shoe size.

Solution: Without specific numerical data from the document, we assume a normal distribution of shoe sizes. If the shoe sizes are normally distributed, the probability of selecting a student with a shoe size greater than the average is 0.5 (50%) because the normal distribution is symmetric about the mean.

Problem 5:

Determine the solutions to the inequality x2+3x4<0x^2 + 3x - 4 < 0.

Solution: First, find the roots of the corresponding equation x2+3x4=0x^2 + 3x - 4 = 0 by factorizing.

x2+3x4=(x+4)(x1)=0x^2 + 3x - 4 = (x + 4)(x - 1) = 0

The roots are: x=4x = -4 x=1x = 1

The inequality x2+3x4<0x^2 + 3x - 4 < 0 holds between the roots: 4<x<1-4 < x < 1

Any questions or further details required?

Feel free to ask any of the following questions for more practice or clarity:

  1. How do you solve quadratic equations by factorization?
  2. What is the cosine rule and when is it used?
  3. How do you calculate the volume of a pyramid?
  4. How do you determine the probability of an event in a normal distribution?
  5. How do you solve polynomial inequalities?

Tip: Always verify the solutions to quadratic equations by substituting them back into the original equation to ensure they satisfy the equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Geometry
Trigonometry
Probability
Inequalities

Formulas

Quadratic equation factorization
Cosine rule
Volume of pyramid formula
Normal distribution probability

Theorems

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Suitable Grade Level

Grades 9-12