Math Problem Statement

Evaluate the expressions in the problems provided in the image.

Solution

Let’s analyze and solve the mathematical problems from the provided image.

Problem 1

Fill in the blanks to evaluate the expression:
45+((227)+5)=45+(___+5)45 + ((22 - 7) + 5) = 45 + ( \_\_\_ + 5 )
45+___=___45 + \_\_\_ = \_\_\_

Step-by-Step Solution:

  1. Simplify 22722 - 7:
    227=1522 - 7 = 15

  2. Substitute 1515 into the equation:
    45+((15)+5)45 + ((15) + 5)

  3. Simplify 15+515 + 5:
    15+5=2015 + 5 = 20

  4. Now the equation becomes:
    45+20=6545 + 20 = 65

Answer:
Fill in the blanks as follows: 45+((227)+5)=45+(15+5)45 + ((22 - 7) + 5) = 45 + (15 + 5)
45+20=6545 + 20 = 65


Problem 2

Evaluate:
4×[((127)+(5×5))÷6]4 \times [ ((12 - 7) + (5 \times 5)) \div 6 ]

Step-by-Step Solution:

  1. Simplify 12712 - 7:
    127=512 - 7 = 5

  2. Simplify 5×55 \times 5:
    5×5=255 \times 5 = 25

  3. Add 5+255 + 25:
    5+25=305 + 25 = 30

  4. Divide 30÷630 \div 6:
    30÷6=530 \div 6 = 5

  5. Multiply 4×54 \times 5:
    4×5=204 \times 5 = 20

Answer:
2020


Problem 3

Evaluate:
4×[(35×210)(110+150)]4 \times \left[ \left( \frac{3}{5} \times \frac{2}{10} \right) - \left( \frac{1}{10} + \frac{1}{50} \right) \right]

Step-by-Step Solution:

  1. Simplify 35×210\frac{3}{5} \times \frac{2}{10}:
    35×210=650=325\frac{3}{5} \times \frac{2}{10} = \frac{6}{50} = \frac{3}{25}

  2. Simplify 110+150\frac{1}{10} + \frac{1}{50} using a common denominator of 50:
    110=550\frac{1}{10} = \frac{5}{50}
    550+150=650=325\frac{5}{50} + \frac{1}{50} = \frac{6}{50} = \frac{3}{25}

  3. Subtract 325325\frac{3}{25} - \frac{3}{25}:
    325325=0\frac{3}{25} - \frac{3}{25} = 0

  4. Multiply 4×04 \times 0:
    4×0=04 \times 0 = 0

Answer:
00


Do you need detailed steps for any specific part? Let me know!


Follow-Up Questions:

  1. How can you verify your answers to complex expressions?
  2. What are the common mistakes to watch for when simplifying fractions?
  3. Can parentheses affect the final outcome of an equation?
  4. Why is finding a common denominator necessary in fraction addition or subtraction?
  5. How do order of operations (PEMDAS) apply in these problems?

Tip: Always double-check your results by re-evaluating the simplified values step-by-step.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Operations
Fractions
Order of Operations (PEMDAS)

Formulas

Addition and Subtraction: a + b, a - b
Multiplication: a × b
Division: a ÷ b
Fraction Multiplication: (a/b) × (c/d) = (a×c)/(b×d)

Theorems

Basic Arithmetic Properties
Order of Operations

Suitable Grade Level

Grades 5-7