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The problem asks for the mass of carbon in 5,000 grams of dry ice, which is solid carbon dioxide (\(CO_2\)).

To solve this:

1. **Molar Mass of \(CO_2\)**:
   - Carbon (C) has an atomic mass of 12 g/mol.
   - Oxygen (O) has an atomic mass of 16 g/mol.
   - So, the molar mass of \(CO_2\) is:
     \[
     12 \, \text{g/mol} + 2 \times 16 \, \text{g/mol} = 44 \, \text{g/mol}
     \]

2. **Proportion of Carbon in \(CO_2\)**:
   - The mass of carbon in one mole of \(CO_2\) is 12 g.
   - The mass fraction of carbon is:
     \[
     \frac{12 \, \text{g}}{44 \, \text{g/mol}} = 0.2727
     \]

3. **Mass of Carbon in 5,000 grams of Dry Ice**:
   - Multiply the mass fraction of carbon by the total mass of dry ice:
     \[
     0.2727 \times 5000 \, \text{g} = 1,363.5 \, \text{g}
     \]
   - Rounded to the nearest gram, the mass of carbon is **1,364 g**.

Would you like further details or clarification on any step?

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Here are 5 related questions to deepen your understanding:

1. How would the answer change if you had a different amount of dry ice?
2. Can you explain how to calculate the molar mass of other molecules?
3. What is the significance of molar mass in chemistry?
4. If the molecular formula was \(CO\) instead of \(CO_2\), how would the mass of carbon change?
5. How would you find the number of moles of \(CO_2\) in 5,000 grams?

**Tip:** The mass fraction of an element in a compound is a quick way to calculate how much of that element is present in a sample of the compound!

The chemical formula for dry ice is CO₂. What is the mass of carbon in 5,000 grams of dry ice? Round to the nearest gram. (O = 16, C = 12)

Learn how to calculate the mass of carbon in 5,000 grams of dry ice (CO₂) by using molar mass and mass fraction. This problem explores key chemistry concepts, such as the molar mass of CO₂ and the calculation of the mass fraction of carbon, suitable for students in Grades 10-12.

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