a. 32 g of solid sulfur (S) reacts with oxygen gas (02) in a closed container producing 80 g of sulfur trioxide (SO3). The reaction obeyed the law of conservation of mass. What is the amount of oxygen gas that reacted?

The law of conservation of mass states that the mass of the reactants must equal the mass of the products in a chemical reaction. Here's how we can apply this to the reaction involving sulfur (S) and oxygen (O₂) to produce sulfur trioxide (SO₃):

Given:
- Mass of sulfur (S) = 32 g
- Mass of sulfur trioxide (SO₃) produced = 80 g
- Mass of oxygen (O₂) reacted = ?

### Step-by-Step Solution:

1. **Mass of products (SO₃)**: The total mass of the products is 80 g, which includes the sulfur and oxygen combined in SO₃.
   
2. **Mass of sulfur (S)**: You are given that 32 g of sulfur reacted.

3. **Mass of oxygen (O₂)**: To find how much oxygen reacted, subtract the mass of sulfur from the total mass of sulfur trioxide produced:
   \[
   \text{Mass of oxygen} = \text{Mass of SO₃} - \text{Mass of sulfur}
   \]
   \[
   \text{Mass of oxygen} = 80 \, \text{g} - 32 \, \text{g} = 48 \, \text{g}
   \]

### Conclusion:
The amount of oxygen gas that reacted is **48 g**.

Would you like further details or have any questions?

Here are 5 related questions you might find useful:
1. What is the chemical equation for the reaction between sulfur and oxygen to form sulfur trioxide?
2. How does the law of conservation of mass apply to chemical reactions?
3. What is the molar mass of sulfur trioxide (SO₃), and how can it be used in stoichiometric calculations?
4. How do we determine the mass of a specific element in a compound from its chemical formula?
5. What are the differences between sulfur dioxide (SO₂) and sulfur trioxide (SO₃)?

**Tip:** When solving mass-related problems, always ensure the units are consistent, and use the law of conservation of mass to check your answers.

32 g of solid sulfur (S) reacts with oxygen gas (O2) in a closed container producing 80 g of sulfur trioxide (SO3). The reaction obeyed the law of conservation of mass. What is the amount of oxygen gas that reacted?

Find out how to calculate the amount of oxygen gas that reacts with sulfur using the law of conservation of mass. This problem explains how 32 g of sulfur combines with oxygen to form 80 g of sulfur trioxide, with step-by-step calculations for students in Grades 6-8.

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