If 43 g of sulfur and 100 g of oxygen are placed into a sealed container and allowed to react. What is the mass of the material in the container after the reaction is completed following the law of conservation of mass?

The **law of conservation of mass** states that in a closed system, mass is neither created nor destroyed in a chemical reaction. Thus, the total mass of the products must equal the total mass of the reactants.

Here, the reactants are sulfur and oxygen. Their masses are:
- Sulfur: 43 g
- Oxygen: 100 g

Since the container is sealed, no mass escapes or enters. The total mass after the reaction is the sum of the masses of sulfur and oxygen:

\[
\text{Total mass} = 43 \, \text{g} + 100 \, \text{g} = 143 \, \text{g}
\]

Therefore, the mass of the material in the container after the reaction is completed is **143 g**.

Would you like more details on the reaction process, or have any other questions?

Here are some related questions to consider:
1. How does the law of conservation of mass apply to chemical equations?
2. What type of reaction occurs when sulfur reacts with oxygen?
3. How would the mass change if the container were not sealed?
4. What are the products when sulfur reacts with oxygen?
5. How can you experimentally verify the law of conservation of mass?

**Tip**: Always ensure a reaction occurs in a closed system to observe the law of conservation of mass effectively.

If 43 g of sulfur and 100 g of oxygen are placed into a sealed container and allowed to react, what is the mass of the material in the container after the reaction is completed following the law of conservation of mass?

Discover how to calculate the total mass of reactants in a sealed container following the law of conservation of mass. This example demonstrates basic arithmetic operations and the application of the law of conservation of mass with 43 g of sulfur and 100 g of oxygen. Suitable for students in Grades 6-8.

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