Math Problem Statement
Three boys A, B and C are throwing a ball to each other. A always throws the ball to B and B always throws the ball to C. But C just as likely to throw the ball to B as to A. Show the process is Markovian. Find the transition matrix and classify the states. Do all the states are ergodic?
Solution
Solution:
Step 1: Understanding the problem
This problem involves a stochastic process where the ball's position among three boys and evolves over time. The process is Markovian if the next state depends only on the current state and not on any past states.
From the problem:
- always throws the ball to .
- always throws the ball to .
- throws the ball either to or , each with a probability of .
We need to:
- Prove the process is Markovian.
- Derive the transition matrix.
- Classify the states.
- Determine if all states are ergodic.
Step 2: Prove the process is Markovian
The process is Markovian because:
- The state of the process at time (who has the ball) depends only on the state at time , i.e., who has the ball at .
- The probabilities of transitioning to the next state are independent of the earlier history of the process.
Step 3: Transition Matrix
The states of the system can be denoted as:
- : The ball is with .
- : The ball is with .
- : The ball is with .
The transition probabilities can be summarized as follows:
- (A always throws to B).
- (B always throws to C).
- , (C throws to A or B with equal probability).
Thus, the transition matrix is:
\begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ \frac{1}{2} & \frac{1}{2} & 0 \end{bmatrix}$$ --- #### **Step 4: Classify the States** 1. **Irreducibility**: - A Markov chain is irreducible if it is possible to go from any state to any other state in a finite number of steps. - In this case, starting from any state ($$A, B, C$$), it is possible to reach any other state due to the transitions. For example: - $$A \to B \to C \to A$$ ensures all states communicate. 2. **Periodicity**: - The period of a state is the greatest common divisor (GCD) of the lengths of all cycles returning to the state. - For $$A$$, the cycle lengths are 3 (e.g., $$A \to B \to C \to A$$). - Similarly, $$B$$ and $$C$$ have cycles of length 3. - All states have a period of 3, so the chain is **periodic**. 3. **Ergodicity**: - A state is ergodic if it is both **irreducible** and **aperiodic**. - Since the chain is periodic, the states are **not ergodic**. --- #### **Step 5: Conclusion** 1. The process is **Markovian** because transitions depend only on the current state. 2. The **transition matrix** is: $$P = \begin{bmatrix} 0 & 1 & 0 \\ 0 & 0 & 1 \\ \frac{1}{2} & \frac{1}{2} & 0 \end{bmatrix}$$ 3. The states $$A, B, C$$ are **periodic** with period 3. 4. The states are **not ergodic** because of periodicity. --- ### **Further Exploration:** 1. What happens to the transition matrix if $$C$$ throws the ball with probabilities other than $$\frac{1}{2}$$? 2. Can the process become ergodic by modifying the rules for $$C$$'s throws? 3. Compute the steady-state probabilities if the chain were ergodic. 4. Analyze how long it takes on average to return to $$A$$ starting from $$A$$. 5. Investigate what happens if $$A, B,$$ and $$C$$ throw the ball randomly. --- ### **Tip**: When classifying Markov chains, always check for irreducibility and periodicity first. These properties are key to understanding the chain's long-term behavior.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Markov Chains
Transition Matrices
State Classification in Markov Processes
Formulas
Transition matrix representation
Periodicity and irreducibility criteria
Theorems
Markov property definition
Ergodicity conditions
Suitable Grade Level
Grades 11-12 or Undergraduate Level
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