To find the margin of error (MOE) for the survey result, we can use the following formula for the margin of error at a 95% confidence level:

$\text{MOE} = Z \times \sqrt{\frac{p(1 - p)}{n}}$

where:

• $Z$ is the Z-score corresponding to the desired confidence level (for 95%, $Z \approx 1.96$)
• $p$ is the sample proportion (76%, or 0.76)
• $n$ is the sample size (1655)

Step-by-Step Solution:

1. Convert 76% to a decimal: $p = 0.76$

2. Compute $p(1 - p)$: $p(1 - p) = 0.76 \times (1 - 0.76) = 0.76 \times 0.24 = 0.1824$

3. Divide by the sample size $n$: $\frac{0.1824}{1655} \approx 0.0001102$

4. Take the square root: $\sqrt{0.0001102} \approx 0.0105$

5. Multiply by the Z-score for a 95% confidence level (1.96): $\text{MOE} = 1.96 \times 0.0105 \approx 0.0206$

6. **Convert