Math Problem Statement

-1,0,1 onto -i,-1,i using three points and their images given formula w-w1/w-w3 * w2-w3/w2-w1 = z-z1/z-z3 * z2-z3/z2-z1

Solution

To find the image of the points 1-1, 00, and 11 under the given transformation, we can use the provided formula:

ww1ww3w2w3w2w1=zz1zz3z2z3z2z1\frac{w - w_1}{w - w_3} \cdot \frac{w_2 - w_3}{w_2 - w_1} = \frac{z - z_1}{z - z_3} \cdot \frac{z_2 - z_3}{z_2 - z_1}

Here, let's assume:

  • z1=1z_1 = -1, z2=0z_2 = 0, z3=1z_3 = 1
  • w1=iw_1 = -i, w2=1w_2 = -1, w3=iw_3 = i

We need to find the corresponding image ww for each zz.

Step 1: Set up the equation for each zz

  1. For z=1z = -1:

    Substitute z=z1=1z = z_1 = -1 into the equation: ww1ww3w2w3w2w1=1z11z3z2z3z2z1\frac{w - w_1}{w - w_3} \cdot \frac{w_2 - w_3}{w_2 - w_1} = \frac{-1 - z_1}{-1 - z_3} \cdot \frac{z_2 - z_3}{z_2 - z_1}

    Simplifying: w+iwi1i1+i=1+111010+1\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = \frac{-1 + 1}{-1 - 1} \cdot \frac{0 - 1}{0 + 1}

  2. For z=0z = 0:

    Substitute z=z2=0z = z_2 = 0 into the equation: ww1ww3w2w3w2w1=0z10z3z2z3z2z1\frac{w - w_1}{w - w_3} \cdot \frac{w_2 - w_3}{w_2 - w_1} = \frac{0 - z_1}{0 - z_3} \cdot \frac{z_2 - z_3}{z_2 - z_1}

    Simplifying: w+iwi1i1+i=1111\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = \frac{1}{-1} \cdot \frac{-1}{1}

  3. For z=1z = 1:

    Substitute z=z3=1z = z_3 = 1 into the equation: ww1ww3w2w3w2w1=1z11z3z2z3z2z1\frac{w - w_1}{w - w_3} \cdot \frac{w_2 - w_3}{w_2 - w_1} = \frac{1 - z_1}{1 - z_3} \cdot \frac{z_2 - z_3}{z_2 - z_1}

    Simplifying: w+iwi1i1+i=2012\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = \frac{2}{0} \cdot \frac{-1}{2}

Step 2: Solve each equation for ww

Given that the transformation must map 1-1 to i-i, 00 to 1-1, and 11 to ii, solve the resulting simplified equations for ww.

For z=1z = -1, solve:

w+iwi1i1+i=0212\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = \frac{0}{-2} \cdot \frac{-1}{2} This equation simplifies to w=iw = -i.

For z=0z = 0, solve:

w+iwi1i1+i=1\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = 1 This equation simplifies to w=1w = -1.

For z=1z = 1, solve:

w+iwi1i1+i=\frac{w + i}{w - i} \cdot \frac{-1 - i}{-1 + i} = -\infty This equation simplifies to w=iw = i.

So the image points are:

  • z=1z = -1 maps to w=iw = -i
  • z=0z = 0 maps to w=1w = -1
  • z=1z = 1 maps to w=iw = i

Would you like to see more details about these transformations, or do you have any questions? Here are five related questions to consider:

  1. How do you solve for ww in each transformation equation?
  2. What is the significance of each term in the transformation formula?
  3. How would the transformation change if the points w1w_1, w2w_2, and w3w_3 were different?
  4. Can this transformation be generalized to map other sets of points?
  5. What type of transformation is this, geometrically?

Tip: Always check the consistency of each step when applying complex transformations, as errors can easily propagate.

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Math Problem Analysis

Mathematical Concepts

Complex Analysis
Conformal Mapping

Formulas

Schwarz-Christoffel formula

Theorems

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Suitable Grade Level

Advanced Mathematics