Math Problem Statement

what os the maclaurin expansion of e^-x

Solution

The Maclaurin series expansion of exe^{-x} is given by:

ex=n=0(x)nn!e^{-x} = \sum_{n=0}^{\infty} \frac{(-x)^n}{n!}

Expanding the first few terms:

ex=1x+x22!x33!+x44!x55!+e^{-x} = 1 - x + \frac{x^2}{2!} - \frac{x^3}{3!} + \frac{x^4}{4!} - \frac{x^5}{5!} + \dots

This series is valid for all real values of xx.

Would you like a deeper explanation or any specific application?

Here are five related questions to expand on this topic:

  1. How is the Maclaurin series derived from the Taylor series?
  2. What is the radius of convergence of this series?
  3. How can this expansion be used to approximate exe^{-x} for small values of xx?
  4. How do we use the Maclaurin series to estimate error in approximations?
  5. Can the Maclaurin series be used to evaluate limits involving exe^{-x}?

Tip: The Maclaurin series for exe^x and exe^{-x} are closely related and can be used to derive hyperbolic functions like coshx\cosh x and sinhx\sinh x.

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Math Problem Analysis

Mathematical Concepts

Maclaurin Series
Exponential Functions
Series Expansion

Formulas

e^(-x) = Σ (-x)^n / n!

Theorems

Maclaurin Series

Suitable Grade Level

Grades 11-12