Math Problem Statement

To improve their approximations, ecologists may use a logistic model, which considers limiting factors to the growth of the population. Deer population is known to have a carrying capacity K, which is the maximum size that a population can have in a given area in order to have enough resources.

In the logistic model, the rate of growth of the population is proportional to the product of the population and the percentage difference between the carrying capacity and the population.

Which of the following differential equations provides an expression for the rate of growth of the population using the logistic model? answers of (dN)/(dt)=rN(1-K), rN(1-KN), r(1-K), rN(1-(N/K)), r(1-(N/K)) or rN(1-(1/K))

Solution

The logistic model describes how a population grows while considering a carrying capacity. The general form of the logistic differential equation is given by:

dNdt=rN(1NK)\frac{dN}{dt} = rN \left( 1 - \frac{N}{K} \right)

where:

  • NN is the population size,
  • tt is time,
  • rr is the intrinsic growth rate of the population,
  • KK is the carrying capacity.

Analysis of the Answer Choices:

  1. dNdt=rN(1K)\frac{dN}{dt} = rN(1-K)
    This form is incorrect because it does not involve NN relative to KK. It treats KK as a constant subtraction, which does not represent the logistic model.

  2. dNdt=rN(1KN)\frac{dN}{dt} = rN(1-KN)
    This equation incorrectly places NN and KK together in a multiplication form, which is not how the logistic model is defined.

  3. dNdt=r(1K)\frac{dN}{dt} = r(1-K)
    This equation does not include NN, which means it does not represent population growth. It’s incorrect.

  4. dNdt=rN(1NK)\frac{dN}{dt} = rN\left(1 - \frac{N}{K}\right)
    This is the correct form of the logistic model equation, where the growth rate is proportional to NN and the term (1NK)\left( 1 - \frac{N}{K} \right) captures the limiting effect of the carrying capacity.

  5. dNdt=r(1NK)\frac{dN}{dt} = r\left(1 - \frac{N}{K}\right)
    This equation is incorrect because it lacks the NN factor, which means it doesn't scale the growth rate by the population size.

  6. dNdt=rN(11K)\frac{dN}{dt} = rN\left(1 - \frac{1}{K}\right)
    This equation incorrectly places 1K\frac{1}{K} as a constant, which does not correctly represent the logistic model.

Final Answer

The correct differential equation for the logistic model is:

dNdt=rN(1NK)\frac{dN}{dt} = rN\left(1 - \frac{N}{K}\right)

Would you like more details or have any further questions?

Related Questions

  1. How do you derive the logistic model equation from first principles?
  2. What are the implications of a high rr value in the logistic model?
  3. How does the population behave when NN approaches KK?
  4. How can we solve the logistic differential equation analytically?
  5. What are some limitations of the logistic growth model?

Tip: The logistic model assumes that resources are evenly distributed and that the carrying capacity is constant, which may not always hold true in real-world scenarios.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Differential Equations
Logistic Growth Model
Population Dynamics

Formulas

dN/dt = rN(1 - N/K)

Theorems

Logistic Growth Model

Suitable Grade Level

Undergraduate level, early calculus