Math Problem Statement

Semesta pembicaraan adalah himpunan bilangan 1, 2, 3, 4, 5. Tentukan nilai logika kalimat-kalimat berikut: a. (∃x). x + 1 < 5, b. (∀x). x ≤ 5, c. (∀x). x + 4 < 10.

Solution

Let's break down and solve the logical statements based on the universe of discourse {1,2,3,4,5}\{1, 2, 3, 4, 5\}:

Given Statements:

  1. The universe of discourse is {1,2,3,4,5}\{1, 2, 3, 4, 5\}.
  2. Determine the truth values of the following:
    • a. (x).x+1<5(\exists x). x + 1 < 5
    • b. (x).x5(\forall x). x \leq 5
    • c. (x).x+4<10(\forall x). x + 4 < 10

Solutions:

a. (x).x+1<5(\exists x). x + 1 < 5

  • This statement means: "There exists an xx in the set {1,2,3,4,5}\{1, 2, 3, 4, 5\} such that x+1<5x + 1 < 5."
  • Let's check each value of xx:
    • x=11+1=2<5x = 1 \rightarrow 1 + 1 = 2 < 5 (True)
    • Since x=1x = 1 satisfies the condition, the statement is true.

b. (x).x5(\forall x). x \leq 5

  • This statement means: "For all xx in the set {1,2,3,4,5}\{1, 2, 3, 4, 5\}, x5x \leq 5."
  • Checking all values:
    • x=1,2,3,4,5x = 1, 2, 3, 4, 5, all of these satisfy x5x \leq 5.
  • Therefore, the statement is true.

c. (x).x+4<10(\forall x). x + 4 < 10

  • This statement means: "For all xx in the set {1,2,3,4,5}\{1, 2, 3, 4, 5\}, x+4<10x + 4 < 10."
  • Checking each value of xx:
    • x=11+4=5<10x = 1 \rightarrow 1 + 4 = 5 < 10 (True)
    • x=22+4=6<10x = 2 \rightarrow 2 + 4 = 6 < 10 (True)
    • x=33+4=7<10x = 3 \rightarrow 3 + 4 = 7 < 10 (True)
    • x=44+4=8<10x = 4 \rightarrow 4 + 4 = 8 < 10 (True)
    • x=55+4=9<10x = 5 \rightarrow 5 + 4 = 9 < 10 (True)
  • Since all values satisfy the condition, the statement is true.

Summary of Truth Values:

  • a. True
  • b. True
  • c. True

Would you like any further details or explanations on any part of this solution?

Here are 5 related questions that expand upon this topic:

  1. What is the difference between x\exists x and x\forall x in logic?
  2. How would the truth values change if the universe was {1,2,3,,10}\{1, 2, 3, \ldots, 10\}?
  3. Can a statement with (x)(\exists x) be false if at least one value of xx satisfies the condition?
  4. How can you negate statements with (x)(\forall x) and (x)(\exists x)?
  5. What other mathematical operations can be used in logical statements besides addition?

Tip: In logic, when you see (x)(\exists x), you only need to find one value that satisfies the condition to make the statement true.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Propositional Logic
Quantifiers (Existential and Universal)
Inequalities

Formulas

x + 1 < 5
x ≤ 5
x + 4 < 10

Theorems

Truth value of statements with existential (∃) and universal (∀) quantifiers

Suitable Grade Level

Grades 10-12