Math Problem Statement
Complete the logical proof for the following argument.
(p Vr) → q q→ t
↑
..t
Step
Proposition
Justification
1
p
Hypothesis
2
pVr
Addition, 1
3
(pVr)→q
Hypothesis
4
q
Modus Ponens, 2, 3
сл
5
q t
Hypothesis
6
t
Modus Ponens,4,3
Note that the justification for each step is either hypothesis or it would include both the name of the law or rule and the step(s) to which it is applied to.
Copy and paste the logical operators when filling in the blanks: V, A, →,~, V, 3.
lote: You can earn partial credit on this problem.
Solution
Let's complete the proof step by step and include the missing details. The goal is to show the argument's conclusion step by step using logical rules.
We are given:
- (Hypothesis)
- (Hypothesis)
- We need to prove .
Proof:
Step | Proposition | Justification |
---|---|---|
1 | Hypothesis | |
2 | Addition (from 1) | |
3 | Hypothesis | |
4 | Modus Ponens (from 2 and 3) | |
5 | Hypothesis | |
6 | Modus Ponens (from 4 and 5) |
Explanation:
- In step 2, we used Addition to infer from . This is a valid step because is true if is true.
- In step 4, we used Modus Ponens on steps 2 and 3. Since we know is true (from step 2) and we have , we can conclude that is true.
- In step 6, we again used Modus Ponens on steps 4 and 5. Since is true and , we conclude that is true, which is the conclusion of the argument.
Would you like further details on any step?
Follow-up questions:
- Can you explain why Modus Ponens is used in this proof?
- What is the purpose of the Addition rule in step 2?
- Why is valid from the hypothesis of ?
- How does the structure of this proof ensure the conclusion ?
- What would happen if we reversed the hypotheses of and ?
Tip:
When working with logical proofs, always identify which statements are your hypotheses and carefully apply rules like Modus Ponens or Addition based on earlier steps.
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Math Problem Analysis
Mathematical Concepts
Propositional Logic
Logical Proof
Modus Ponens
Formulas
Modus Ponens: If (p → q) and p, then q
Addition: From p, infer p ∨ r
Theorems
Modus Ponens
Addition
Suitable Grade Level
Undergraduate/Logic Courses
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