Math Problem Statement

Complete the logical proof for the following argument.

(p Vr) → q q→ t

..t

Step

Proposition

Justification

1

p

Hypothesis

2

pVr

Addition, 1

3

(pVr)→q

Hypothesis

4

q

Modus Ponens, 2, 3

сл

5

q t

Hypothesis

6

t

Modus Ponens,4,3

Note that the justification for each step is either hypothesis or it would include both the name of the law or rule and the step(s) to which it is applied to.

Copy and paste the logical operators when filling in the blanks: V, A, →,~, V, 3.

lote: You can earn partial credit on this problem.

Solution

Let's complete the proof step by step and include the missing details. The goal is to show the argument's conclusion step by step using logical rules.

We are given:

  1. (pr)q(p \lor r) \rightarrow q (Hypothesis)
  2. qtq \rightarrow t (Hypothesis)
  3. We need to prove tt.

Proof:

StepPropositionJustification
1ppHypothesis
2prp \lor rAddition (from 1)
3(pr)q(p \lor r) \rightarrow qHypothesis
4qqModus Ponens (from 2 and 3)
5qtq \rightarrow tHypothesis
6ttModus Ponens (from 4 and 5)

Explanation:

  • In step 2, we used Addition to infer prp \lor r from pp. This is a valid step because prp \lor r is true if pp is true.
  • In step 4, we used Modus Ponens on steps 2 and 3. Since we know prp \lor r is true (from step 2) and we have (pr)q(p \lor r) \rightarrow q, we can conclude that qq is true.
  • In step 6, we again used Modus Ponens on steps 4 and 5. Since qq is true and qtq \rightarrow t, we conclude that tt is true, which is the conclusion of the argument.

Would you like further details on any step?

Follow-up questions:

  1. Can you explain why Modus Ponens is used in this proof?
  2. What is the purpose of the Addition rule in step 2?
  3. Why is prp \lor r valid from the hypothesis of pp?
  4. How does the structure of this proof ensure the conclusion tt?
  5. What would happen if we reversed the hypotheses of qq and tt?

Tip:

When working with logical proofs, always identify which statements are your hypotheses and carefully apply rules like Modus Ponens or Addition based on earlier steps.

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Math Problem Analysis

Mathematical Concepts

Propositional Logic
Logical Proof
Modus Ponens

Formulas

Modus Ponens: If (p → q) and p, then q
Addition: From p, infer p ∨ r

Theorems

Modus Ponens
Addition

Suitable Grade Level

Undergraduate/Logic Courses