Math Problem Statement

Complete the given table. Exponential Form

Logarithmic Form log2^(2) = 1 log4

1 256

= −4 log4^(16) = 2 log10^(100000) = 5 log3^(81) = 4 log4^(1) = 0

Solution

Let's break down and complete the table by converting between exponential and logarithmic forms.

The given logarithmic expressions in the form logb(a)=c\log_b(a) = c can be rewritten into exponential form using the rule:

logb(a)=cmeansbc=a\log_b(a) = c \quad \text{means} \quad b^c = a

Here’s how it works:

  1. log2(2)=1\log_2(2) = 1:

    • Exponential form: 21=22^1 = 2
  2. log4(x)=4\log_4(x) = -4:

    • We convert it to exponential form: 44=x4^{-4} = x Solving, we get x=144=1256x = \frac{1}{4^4} = \frac{1}{256}.
    • Exponential form: 44=12564^{-4} = \frac{1}{256}
  3. log4(16)=2\log_4(16) = 2:

    • Exponential form: 42=164^2 = 16
  4. log10(100000)=5\log_{10}(100000) = 5:

    • Exponential form: 105=10000010^5 = 100000
  5. log3(81)=4\log_3(81) = 4:

    • Exponential form: 34=813^4 = 81
  6. log4(1)=0\log_4(1) = 0:

    • Exponential form: 40=14^0 = 1

Completed Table:

Logarithmic FormExponential Form
log2(2)=1\log_2(2) = 121=22^1 = 2
log4(x)=4\log_4(x) = -444=12564^{-4} = \frac{1}{256}
log4(16)=2\log_4(16) = 242=164^2 = 16
log10(100000)=5\log_{10}(100000) = 5105=10000010^5 = 100000
log3(81)=4\log_3(81) = 434=813^4 = 81
log4(1)=0\log_4(1) = 040=14^0 = 1

Would you like a further breakdown of any of these conversions or more details? Here are some related questions:

  1. What is the general relationship between logarithms and exponents?
  2. How do you solve for unknowns in logarithmic equations?
  3. How can logarithmic properties simplify complex equations?
  4. Can logarithms be used to solve exponential growth problems?
  5. What are common mistakes when converting between logarithmic and exponential forms?

Tip: Always remember that logb(1)=0\log_b(1) = 0 for any base bb, since b0=1b^0 = 1.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponents

Formulas

log_b(a) = c means b^c = a
b^0 = 1 for any base b
b^{-n} = 1/(b^n)

Theorems

Laws of Logarithms
Exponentiation Rules

Suitable Grade Level

Grades 9-12