Math Problem Statement

  1. The vertices of a variable triangle are (3, 4), (5cos0, 5sin0), and (5sin0,-5cos0), where θ ∈ R. The locus of its orthocenter is a) (x+y-1)²+(x-y-7)² = 100 c) (x+y-7)²+(x+y-1)² = 100 b) (x+y-7)²+(x-y-1)²=100 d) (x+y-7)²+(x-y+1)² = 100 for this any trian gle drawing

Solution

Here is a plot of the triangle for different values of θ\theta, showing how the triangle changes as θ\theta varies. The red point represents the fixed vertex A(3,4)A(3, 4), while the other two vertices, B(5cosθ,5sinθ)B(5\cos\theta, 5\sin\theta) and C(5sinθ,5cosθ)C(5\sin\theta, -5\cos\theta), move according to θ\theta.

Next, to find the locus of the orthocenter, we need to calculate the intersection point of the altitudes for each value of θ\theta. Would you like to proceed with the algebraic solution to derive the equation of the orthocenter's locus?

Here are five questions to consider:

  1. How is the slope of a line between two points calculated?
  2. What is the relationship between the slopes of perpendicular lines?
  3. How do you find the equation of a line given a point and a slope?
  4. What is an orthocenter in a triangle, and how is it related to altitudes?
  5. How does varying θ\theta affect the positions of the triangle's vertices?

Tip: The orthocenter is always the point where the three altitudes of a triangle intersect.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry
Coordinate Geometry
Locus
Orthocenter

Formulas

Slope of a line between two points
Equation of a line through a point with a given slope

Theorems

Orthocenter properties
Altitude intersection theorem
Perpendicular slopes

Suitable Grade Level

Grades 11-12