Math Problem Statement

A rigid right triangle with side length AB = 5 , AC = 4 AND BC = 3 . If side AB can slide along x and y axes . Find the locus of C

Solution

We are given a rigid right triangle ABC\triangle ABC with side lengths AB=5AB = 5, AC=4AC = 4, and BC=3BC = 3. The triangle can slide along the xx-axis and yy-axis, meaning that point AA moves along the axes, and we are asked to find the locus of point CC.

Step-by-Step Breakdown:

  1. Coordinate Setup:

    • Let the coordinates of point AA be (x1,y1)(x_1, y_1).
    • Since AB=5AB = 5, and point BB is constrained to slide along the axes, point BB is either on the xx-axis or yy-axis. Thus, we assume that the position of BB is at the origin, i.e., B(0,0)B(0, 0).
  2. Triangle Relations: Since AB=5AB = 5, the distance between point A(x1,y1)A(x_1, y_1) and point B(0,0)B(0, 0) must satisfy the equation of a circle centered at BB with radius 5: x12+y12=25.x_1^2 + y_1^2 = 25.

  3. Finding the Locus of CC: The distance from AA to CC is given as AC=4AC = 4, and the distance from BB to CC is BC=3BC = 3. Since AA and BB are on fixed axes and CC forms a right triangle, we apply the Pythagorean theorem. This results in the coordinates of CC depending on the position of AA and its movement.

However, to fully determine the mathematical equation for the locus,

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Locus of a Point
Pythagorean Theorem
Distance Formula

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)
Equation of a circle: x^2 + y^2 = r^2 (for a circle centered at the origin)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-12