Math Problem Statement

The graph of y = x^3 - 2x^2 - 5x + 2 has a local maximum at:

Solution

The given function is y=x32x25x+2y = x^3 - 2x^2 - 5x + 2. We found the critical points by solving the first derivative and determining the concavity with the second derivative. Here are the results:

  • The critical points are x0.786x \approx -0.786 and x2.120x \approx 2.120.
  • The second derivative test shows that at x0.786x \approx -0.786, the second derivative is negative, indicating a local maximum. At x2.120x \approx 2.120, the second derivative is positive, indicating a local minimum.
  • Evaluating the function at these points gives approximate values of:
    • y(0.786)4.209y(-0.786) \approx 4.209 (local maximum)
    • y(2.120)8.061y(2.120) \approx -8.061 (local minimum)

Therefore, the local maximum occurs at the point (0.786,4.209)(-0.786, 4.209), which corresponds to option (D).

Would you like more details or have any questions?

Here are 5 related questions to expand on this:

  1. How do you find critical points of a function?
  2. What does the second derivative test indicate?
  3. What is the significance of concavity in determining local maxima or minima?
  4. How would you graph a cubic function like this one?
  5. How can you confirm whether a point is a local maximum or minimum graphically?

Tip: Always check the second derivative to confirm whether a critical point is a maximum or minimum!

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Math Problem Analysis

Mathematical Concepts

Calculus
Critical Points
Second Derivative Test
Polynomial Functions

Formulas

First derivative: dy/dx = 3x^2 - 4x - 5
Second derivative: d²y/dx² = 6x - 4

Theorems

Second Derivative Test

Suitable Grade Level

Grades 11-12 (Calculus)