Math Problem Statement
The table below shows the relationship between daytime temperature and volume of heating fuel sold at a particular domestic energy shop.
Temperature 15 17 18 18 19 20 21 22 24 25 Fuel Sold 135 130 85 50 45 40 20 25 15 10
a) Determine which is the dependent (Y) variable and which is the independent (X) variable. Give reasons for your answer. (4 Marks) b) Draw a scatter plot to represent the data (4 Marks) c) Comment on the strength and direction of the linear relationship between the variables. (2 Marks) d) Find the regression equation of the data (8 Marks) Interpret your results in (d) above.
Solution
a) Determine the dependent (Y) and independent (X) variables.
-
Independent variable (X): Temperature
Temperature is controlled or observed as an influencing factor. It does not depend on fuel sales, but it is likely to affect them. -
Dependent variable (Y): Fuel Sold
Fuel sold depends on temperature because as the temperature changes, the need for heating fuel varies.
b) Draw a scatter plot to represent the data.
I'll first create the scatter plot.import matplotlib.pyplot as plt
Data
temperature = [15, 17, 18, 18, 19, 20, 21, 22, 24, 25] fuel_sold = [135, 130, 85, 50, 45, 40, 20, 25, 15, 10]
Scatter Plot
plt.figure(figsize=(8, 6)) plt.scatter(temperature, fuel_sold, marker='o', edgecolor='black') plt.title("Scatter Plot: Temperature vs Fuel Sold") plt.xlabel("Temperature (°C)") plt.ylabel("Fuel Sold (units)") plt.grid(True) plt.show() <<ImageDisplayed>>successHere is the scatter plot showing the relationship between temperature and fuel sold.
c) Comment on the strength and direction of the linear relationship.
From the scatter plot:
- Direction: The relationship appears to be negative; as the temperature increases, fuel sales decrease.
- Strength: The points are somewhat close to a linear pattern, indicating a moderately strong negative correlation.
d) Find the regression equation of the data.
I'll calculate the regression equation in the form .import numpy as np from scipy.stats import linregress
Calculate the regression line
slope, intercept, r_value, p_value, std_err = linregress(temperature, fuel_sold)
Regression equation
regression_equation = f"Y = {intercept:.2f} + {slope:.2f}X"
Display results
regression_equation, r_value**2('Y = 311.69 + -12.87X', 0.7745727966156946)('Y = 311.69 + -12.87X', 0.7745727966156946)successThe regression equation for the data is:
Where:
- : Fuel Sold
- : Temperature
The value is approximately , meaning about 77.5% of the variability in fuel sales is explained by the temperature.
Interpretation of Results:
- The negative slope () indicates that for each 1°C increase in temperature, the fuel sales decrease by approximately 12.87 units.
- The intercept () represents the estimated fuel sold when the temperature is 0°C, though this value might not be practically meaningful in this context.
Let me know if you want a deeper explanation or further analysis!
Expanded Questions:
- How would the strength of the relationship be interpreted if was lower?
- Could other factors besides temperature affect fuel sales? How would you model them?
- What are the limitations of using this regression model to predict fuel sales for temperatures outside the given range?
- How might outliers affect the regression line and ?
- How could you test if the relationship is statistically significant?
Tip:
Always visually inspect your data with scatter plots before fitting a regression model to identify potential anomalies or nonlinear patterns.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear regression
Correlation
Scatter plots
Formulas
Regression equation: Y = a + bX
Correlation coefficient formula
Theorems
Least squares method
Properties of correlation coefficients
Suitable Grade Level
Grades 10-12