Math Problem Statement

Girls emerge from adolescence feeling quite differently about themselves, acco several studies. Suppose a number of randomly selected girls in the Ithaca-Binghamton area of New York State yielded the following data: X y (Girl's age in years old) (Self-esteem: 0 to 100 scale) 8 11 14 13 16 72 64 82 53 41 46 1. 2. 3. 4 Construct a scatterplot of the data. Calculate the values for m and for b (by hand), and then write the least-squares equation in D=mx+b form. Use the least-squares regression equation to predict self-esteem for a girl of age (i) 9 and (ii) 15 Use the two (xv)-noints calculated in number 3 to lot the least-squares

Solution

Let's break down the problem into several steps to answer each question clearly.

1. Scatterplot of the data

We are given the data for the girl's age (X) and self-esteem scores (Y):

Age (X)Self-Esteem (Y)
872
1164
1482
1353
1641

I will generate the scatterplot for this data.

2. Calculate the values for the slope (m) and intercept (b) by hand

The formula for the least-squares regression line is:

y=mx+by = mx + b

Where:

  • mm is the slope of the line, and
  • bb is the y-intercept.

The formulas to calculate mm and bb are:

m=nXYXYnX2(X)2m = \frac{n\sum{XY} - \sum{X}\sum{Y}}{n\sum{X^2} - (\sum{X})^2}

b=YmXnb = \frac{\sum{Y} - m\sum{X}}{n}

Let’s compute these values step-by-step.

  • n=5n = 5 (since there are 5 pairs of data points).

  • First, calculate the necessary sums:

    X=8+11+14+13+16=62\sum X = 8 + 11 + 14 + 13 + 16 = 62 Y=72+64+82+53+41=312\sum Y = 72 + 64 + 82 + 53 + 41 = 312 XY=(8×72)+(11×64)+(14×82)+(13×53)+(16×41)=576+704+1148+689+656=3773\sum XY = (8 \times 72) + (11 \times 64) + (14 \times 82) + (13 \times 53) + (16 \times 41) = 576 + 704 + 1148 + 689 + 656 = 3773 X2=82+112+142+132+162=64+121+196+169+256=806\sum X^2 = 8^2 + 11^2 + 14^2 + 13^2 + 16^2 = 64 + 121 + 196 + 169 + 256 = 806

Now, substitute these values into the formula for mm:

m=5(3773)(62)(312)5(806)(62)2=188651934440303844=5211862.80m = \frac{5(3773) - (62)(312)}{5(806) - (62)^2} = \frac{18865 - 19344}{4030 - 3844} = \frac{521}{186} \approx 2.80

Now for bb:

b=3122.80(62)5=312173.65=138.45=27.68b = \frac{312 - 2.80(62)}{5} = \frac{312 - 173.6}{5} = \frac{138.4}{5} = 27.68

So the equation of the least-squares regression line is:

y=2.80x+27.68y = 2.80x + 27.68

3. Predict self-esteem for ages 9 and 15

Now we can use the regression equation y=2.80x+27.68y = 2.80x + 27.68 to predict the self-esteem for a girl aged 9 and 15.

(i) Age 9:

y=2.80(9)+27.68=25.2+27.68=52.88y = 2.80(9) + 27.68 = 25.2 + 27.68 = 52.88

(ii) Age 15:

y=2.80(15)+27.68=42+27.68=69.68y = 2.80(15) + 27.68 = 42 + 27.68 = 69.68

So, the predicted self-esteem is approximately:

  • For a 9-year-old girl: 52.88
  • For a 15-year-old girl: 69.68

4. Plot the least-squares regression line

Using the two points calculated in step 3, the line passes through:

  • (9, 52.88)
  • (15, 69.68)

I will now generate the scatterplot with this regression line.

Let me compute and display the scatterplot and lineIt seems like I can’t do more advanced data analysis right now. Please try again later.

You can use the equation y=2.80x+27.68y = 2.80x + 27.68 to manually plot the regression line on a scatterplot. If you have further questions, feel free to ask!

Would you like details on any of the steps or have more questions?

Here are five questions to consider:

  1. How is the slope mm related to the trend in the data?
  2. Why is the least-squares regression method preferred for such data?
  3. How do changes in age (X) affect the prediction of self-esteem (Y)?
  4. Can this model predict self-esteem accurately for ages outside the given range?
  5. What assumptions do we make when using least-squares regression?

Tip: Always check the residuals to see how well your regression model fits the data!

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Math Problem Analysis

Mathematical Concepts

Statistics
Linear Regression
Scatterplot

Formulas

Least-squares regression line: y = mx + b
Slope formula: m = [nΣXY - ΣXΣY] / [nΣX^2 - (ΣX)^2]
Intercept formula: b = [ΣY - mΣX] / n

Theorems

Least-squares regression theorem

Suitable Grade Level

Grades 10-12