Math Problem Statement

The data show systolic and diastolic blood pressure of certain people. Find the regression​ equation, letting the systolic reading be the independent​ (x) variable. If one of these people has a systolic blood pressure of 118 mm​ Hg, what is the best predicted diastolic blood​ pressure? Systolic 150 124 149 120 114 135 136 116

Diastolic 109 91 110 85 82 74 72 87 LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. Question content area bottom Part 1 What is the regression​ equation? ModifyingAbove y with caretequals

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Solution

To find the regression equation, we first need to calculate the slope (b) and the intercept (a) of the line. The regression equation can be written as:

y^=a+bx\hat{y} = a + bx

Where:

  • y^\hat{y} is the predicted diastolic blood pressure,
  • xx is the systolic blood pressure,
  • aa is the intercept,
  • bb is the slope of the regression line.

Step 1: Calculate the Mean of X and Y

Let's denote:

  • xx as systolic blood pressure,
  • yy as diastolic blood pressure.

Given dataTo find the regression equation, we first need to calculate the slope (b) and the intercept (a) of the line. The regression equation can be written as:

y^=a+bx\hat{y} = a + bx

Where:

  • y^\hat{y} is the predicted diastolic blood pressure,
  • xx is the systolic blood pressure,
  • aa is the intercept,
  • bb is the slope of the regression line.

Step 1: Calculate the Mean of X and Y

Let's denote:

  • xx as systolic blood pressure,
  • yy as diastolic blood pressure.

Given

  • Systolic (X): 150, 124, 149, 120, 114, 135, 136, 116
  • Diastolic (Y): 109, 91, 110, 85, 82, 74, 72, 87

Calculate the means: xˉ=xn,yˉ=yn\bar{x} = \frac{\sum x}{n}, \quad \bar{y} = \frac{\sum y}{n}

Step 2: Calculate the Slope (b)

The slope bb is given by:

b=(xxˉ)(yyˉ)(xxˉ)2b = \frac{\sum (x - \bar{x})(y - \bar{y})}{\sum (x - \bar{x})^2}

Step 3: Calculate the Intercept (a)

The intercept aa is given by:

a=yˉbxˉa = \bar{y} - b\bar{x}

Let's calculate these values.The regression equation, with systolic blood pressure as the independent variable (x), is:

y^=15.44+0.56x\hat{y} = 15.44 + 0.56x

Step 4: Predict the Diastolic Blood Pressure

To predict the diastolic blood pressure when the systolic blood pressure is 118 mm Hg, substitute x=118x = 118 into the regression equation:

y^=15.44+0.56(118)\hat{y} = 15.44 + 0.56(118)

Let's calculate this value.The best predicted diastolic blood pressure for a systolic reading of 118 mm Hg is approximately 81.73 mm Hg.

Would you like any more details or have any questions? Here are a few related questions you might find useful:

  1. How is the Pearson correlation coefficient calculated?
  2. What does the slope of the regression line represent in this context?
  3. How can we assess the accuracy of this regression model?
  4. What is the significance of the intercept in the regression equation?
  5. How would the prediction change if the systolic value was different?

Tip: Always check the residuals (differences between actual and predicted values) to understand how well your regression model fits the data.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Correlation

Formulas

y = a + bx (Regression Equation)
b = Σ(x - x̄)(y - ȳ) / Σ(x - x̄)² (Slope Formula)
a = ȳ - b * x̄ (Intercept Formula)

Theorems

Least Squares Method
Pearson Correlation Coefficient

Suitable Grade Level

Grades 10-12