Math Problem Statement

A grocery store manager did a study to look at the relationship between the amount of time (in minutes) customers spend in the store and the amount of money (in dollars) they spend. The results of the survey are shown below.

Time 18 24 9 32 12 17 22 28 15 21 19 Money 31 30 26 79 24 37 45 88 22 35 25

A. r = [ Select ]

B. r2 = [ Select ]

C. Find the equation of the least squares regression line:

[ Select ] + [ Select ] x

D. What does the regression line predict for the amount of money a person will spend who shops for 20 minutes? [ Select ]

E. Test the hypothesis that there is a linear correlation between the time spent in the market and the money spent at the market. Use a level of significance of 0.05.

H0: r = 0 Ha: r Not Equal to 0

p-Value = [ Select ]

[ Select ]

Solution

Let's break down each part of this problem step by step.

A. r = Pearson Correlation Coefficient

The Pearson correlation coefficient (r) measures the strength and direction of the linear relationship between two variables. It can be calculated using the formula:

[ r = \frac{n \sum{xy} - (\sum{x})(\sum{y})}{\sqrt{[n \sum{x^2} - (\sum{x})^2][n \sum{y^2} - (\sum{y})^2]}} ]

Where:

  • nn is the number of data points (in this case, 11 pairs),
  • xx represents the time spent,
  • yy represents the money spent.

I'll calculate rr for you. Let me process the values. numpy as np

Given data

time_spent = np.array([18, 24, 9, 32, 12, 17, 22, 28, 15, 21, 19]) money_spent = np.array([31, 30, 26, 79, 24, 37, 45, 88, 22, 35, 25])

Calculate Pearson correlation coefficient

r = np.corrcoef(time_spent, money_spent)[0, 1] r### A. r = 0.814

The Pearson correlation coefficient rr is approximately 0.814, which indicates a strong positive linear relationship between the amount of time spent in the store and the amount of money spent.

B. r² = Coefficient of Determination

The coefficient of determination r2r^2 represents the proportion of the variance in the dependent variable that is predictable from the independent variable. It is calculated as:

r2=(r)2r^2 = (r)^2

Let me calculate r2r^2. Calculate r^2 r_squared = r**2 r_squared### B. r² = 0.662

The coefficient of determination r2r^2 is approximately 0.662. This means that about 66.2% of the variability in the money spent is explained by the amount of time spent in the store.

C. Equation of the Least Squares Regression Line

The equation of the least squares regression line is given by:

y=a+bxy = a + bx

Where:

  • b=nxy(x)(y)nx2(x)2b = \frac{n \sum{xy} - (\sum{x})(\sum{y})}{n \sum{x^2} - (\sum{x})^2} is the slope,
  • a=ybxna = \frac{\sum{y} - b \sum{x}}{n} is the y-intercept.

I'll calculate the equation for you now. Calculate slope (b) and intercept (a) for the regression line n = len(time_spent) sum_x = np.sum(time_spent) sum_y = np.sum(money_spent) sum_x_squared = np.sum(time_spent**2) sum_xy = np.sum(time_spent * money_spent)

Calculate slope (b)

b = (n * sum_xy - sum_x * sum_y) / (n * sum_x_squared - sum_x**2)

Calculate intercept (a)

a = (sum_y - b * sum_x) / n

a, b### C. Equation of the Least Squares Regression Line

The equation of the least squares regression line is:

y=13.547+2.724xy = -13.547 + 2.724x

Where:

  • yy is the money spent,
  • xx is the time spent in minutes.

D. Prediction for 20 Minutes of Shopping

To predict the amount of money spent when a person spends 20 minutes in the store, we can plug x=20x = 20 into the regression equation:

y=13.547+2.724(20)y = -13.547 + 2.724(20)

Let's calculate that. Predict money spent when time is 20 minutes time_20 = 20 predicted_money_20 = a + b * time_20 predicted_money_20It seems like I can’t do more advanced data analysis right now. Please try again later. However, I can still provide further explanations or assist with any other part of the question. Let me know how you would like to proceed!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Correlation
Linear Regression
Hypothesis Testing
Statistics

Formulas

Pearson Correlation Coefficient: r = (n Σxy - (Σx)(Σy)) / √[(n Σx² - (Σx)²)(n Σy² - (Σy)²)]
Least Squares Regression Line: y = a + bx
Coefficient of Determination: r² = (r)²

Theorems

Pearson's Correlation Theorem
Linear Regression Theorem

Suitable Grade Level

Grades 11-12