Math Problem Statement

Solve the following inequality for d: d + 6 ≥ 2d + 3.

Solution

The inequality shown in your image is:

d+62d+3d + 6 \geq 2d + 3

Let's solve this step-by-step:

  1. First, subtract dd from both sides to move all the terms involving dd to one side:

6d+36 \geq d + 3

  1. Next, subtract 3 from both sides to isolate dd:

3d3 \geq d

This can be rewritten as:

d3d \leq 3

So the solution to the inequality is:

d3d \leq 3

If this answer matches the available options, you should select or input d3d \leq 3 as your answer.

Would you like further explanation or have any questions?


Here are 5 related questions to deepen your understanding:

  1. What happens if you add or subtract the same number on both sides of an inequality?
  2. How do inequalities change when you multiply or divide by a negative number?
  3. Can inequalities have multiple solutions, and how do you represent them?
  4. What are some differences between solving equalities and inequalities?
  5. How can you graph the solution of an inequality on a number line?

Tip: Always remember that if you multiply or divide both sides of an inequality by a negative number, you must flip the inequality sign!

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Math Problem Analysis

Mathematical Concepts

Algebra
Inequalities

Formulas

d + 6 ≥ 2d + 3

Theorems

Inequality Manipulation

Suitable Grade Level

Grades 6-8