The cost of a chair and    a bench are Rs. 200 and    Rs. 350 respectively. The total cost for all the pieces must not exceed   e Rs 8,000. Represent this inequation form

To represent this problem in the form of an inequation, let:

- \( x \) be the number of chairs.
- \( y \) be the number of benches.

The cost of one chair is Rs. 200, and the cost of one bench is Rs. 350. The total cost of \( x \) chairs and \( y \) benches is given by:

\[
200x + 350y
\]

This total cost must not exceed Rs. 8,000, so we set up the inequality as follows:

\[
200x + 350y \leq 8000
\]

This is the inequation representing the situation.

Would you like more details on solving this type of problem?

Here are 5 related questions to expand on the concept:
1. How would you solve this inequation for \( y \) in terms of \( x \)?
2. Can you graph this inequality and explain the feasible region?
3. How would you modify the inequality if the total budget increased to Rs. 10,000?
4. If you can only buy whole numbers of chairs and benches, how would that affect the inequality solution?
5. What happens if the price of the chair increases to Rs. 250?

**Tip:** Always ensure to check the boundary conditions when working with inequalities to find feasible solutions.

The cost of a chair and a bench are Rs. 200 and Rs. 350 respectively. The total cost for all the pieces must not exceed Rs 8,000. Represent this in inequation form.

Learn how to represent a real-world situation using a linear inequality. This problem involves finding the maximum total cost of chairs and benches given specific prices and constraints. Key concepts include linear inequalities and algebra. Suitable for students in Grades 8-10.

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