Math Problem Statement

Solve and complete tables for linear equations: y = 3x, y = 2x, y = x + 3, y = 4x - 1, y = 2x + 5.

Solution

Let's go through the equations and check the tables for accuracy.

1. y=3xy = 3x

For this equation, we multiply the value of xx by 3 to get yy.

  • x=0x = 0, y=3(0)=0y = 3(0) = 0
  • x=1x = 1, y=3(1)=3y = 3(1) = 3
  • x=2x = 2, y=3(2)=6y = 3(2) = 6

This table is correct.

2. y=2xy = 2x

Here, we multiply the value of xx by 2 to get yy.

  • x=2x = -2, y=2(2)=4y = 2(-2) = -4 (The table has y=2y = -2, so this is incorrect)
  • x=1x = -1, y=2(1)=2y = 2(-1) = -2 (Correct)
  • x=0x = 0, y=2(0)=0y = 2(0) = 0
  • x=1x = 1, y=2(1)=2y = 2(1) = 2
  • x=2x = 2, y=2(2)=4y = 2(2) = 4

So the first entry in the yy-column should be corrected to 4-4.

3. y=x+3y = x + 3

For this, we add 3 to each xx-value to get yy.

  • x=3x = -3, y=(3)+3=0y = (-3) + 3 = 0
  • x=0x = 0, y=0+3=3y = 0 + 3 = 3
  • x=3x = 3, y=3+3=6y = 3 + 3 = 6
  • x=6x = 6, y=6+3=9y = 6 + 3 = 9

The table is missing some values but seems correct for the provided yy-values.

4. y=4x1y = 4x - 1

Here, multiply xx by 4 and subtract 1.

  • x=0x = 0, y=4(0)1=1y = 4(0) - 1 = -1
  • x=1x = 1, y=4(1)1=3y = 4(1) - 1 = 3
  • x=2x = 2, y=4(2)1=7y = 4(2) - 1 = 7
  • x=3x = 3, y=4(3)1=11y = 4(3) - 1 = 11

There is a mistake in the table; for x=0x = 0, yy should be 1-1.

5. y=2x+5y = 2x + 5

Here, multiply xx by 2 and add 5.

  • x=2x = -2, y=2(2)+5=1y = 2(-2) + 5 = 1
  • x=1x = -1, y=2(1)+5=3y = 2(-1) + 5 = 3
  • x=0x = 0, y=2(0)+5=5y = 2(0) + 5 = 5
  • x=1x = 1, y=2(1)+5=7y = 2(1) + 5 = 7
  • x=2x = 2, y=2(2)+5=9y = 2(2) + 5 = 9

The table has an incorrect entry for x=2x = -2, as the correct value should be y=1y = 1.

Summary of Corrections:

  1. Problem 2: For x=2x = -2, yy should be 4-4.
  2. Problem 4: For x=0x = 0, yy should be 1-1.
  3. Problem 5: For x=2x = -2, yy should be 11.

Would you like more details or explanations on any of these?

Here are some follow-up questions you can consider:

  1. What happens to the values of yy if we change the slope of the linear equations?
  2. How would the equations change if we introduced negative slopes?
  3. Can you graph these equations and observe the patterns they form?
  4. How would you interpret the slope and intercept for each of these equations?
  5. Can you find real-life examples where these linear equations might apply?

Tip: Always verify your table by substituting each xx-value back into the equation to ensure the corresponding yy-values are accurate.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope
Intercept

Formulas

y = 3x
y = 2x
y = x + 3
y = 4x - 1
y = 2x + 5

Theorems

Linear Equation Formula
Slope-Intercept Form

Suitable Grade Level

Grades 6-8