the options for the first one are : 1/330, 1/110, 110, 330                                                                                                                                                               The options for the second one are : (60, 1,100), (60, 3,300), (60, 6,600), (60, 19,800)

Given the options, we can select the correct answers based on our calculations:

1. For the slope of the line:
\[ \text{slope} = 110 \text{ meters per minute} \]
So the correct option is:
\[ 110 \]

2. For the point on the line after 60 minutes:
\[ \text{Distance after 60 minutes} = 6600 \text{ meters} \]
So the correct option is:
\[ (60, 6600) \]

So the correct answers are:
- The slope of the line is \( 110 \).
- A point on the line after 60 minutes is \( (60, 6600) \).

Would you like more details or have any questions?

Here are some questions you might find interesting:
1. How do you convert minutes into hours in rate calculations?
2. What is the difference between speed and velocity?
3. How can you use the slope to predict values for different times?
4. What other real-world scenarios can be modeled with a linear relationship?
5. How do you find the y-intercept in a distance-time graph?

**Tip:** Always double-check your unit conversions, especially when dealing with time and distance, to ensure your calculations are accurate.

Learn how to solve practice problems involving linear equations and rate of change. This problem focuses on calculating slope and finding points on a line after a given time. Suitable for students in Grades 7-9.

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