The equation given is a linear equation in the slope-intercept form:

$y = mx + b$

Here, $m = -2$ is the slope of the line, and $b = 5$ is the y-intercept. This means the line crosses the y-axis at the point $(0, 5)$ and has a slope of $-2$, indicating that for every 1 unit increase in $x$, the value of $y$ decreases by 2 units.

Basic Properties:

1. Slope: $-2$ – The line is decreasing because the slope is negative.

2. Y-intercept: 5 – This is the point where the line crosses the y-axis.

3. X-intercept: To find this, set $y = 0$ and solve for $x$:

   $0 = 5 - 2x$

   $2x = 5$

   $x = \frac{5}{2} = 2.5$

   So, the line crosses the x-axis at $(2.5, 0)$.

Would you like a more detailed explanation, a graph of this line, or assistance with a specific question?

Relative Questions:

1. What is the slope of a line perpendicular to $y = 5 - 2x$?
2. How would the graph change if the equation were $y = 5 + 2x$?
3. What is the equation of a line parallel to $y = 5 - 2x$ that passes through the point $(1, 3)$?
4. How do you convert this equation to standard form?
5. How would you find the distance between a point and this line?

Tip: When graphing a line, it's useful to identify both the x-intercept and y-intercept for a quick sketch.