The problem asks to complete the table for the equation $x + 2y = 1$ and to graph the equation.

Let's break down the equation and solve for $y$ in terms of $x$:

$x + 2y = 1$ $2y = 1 - x$ $y = \frac{1 - x}{2}$

Now, using this equation, let's find the missing values for $y$ corresponding to the given $x$ values in the table:

1. When $x = 0$: $y = \frac{1 - 0}{2} = \frac{1}{2} = 0.5$ (This value is already given as 0.5.)

2. When $x = 1$: $y = \frac{1 - 1}{2} = \frac{0}{2} = 0$ (This value is already given as 0.)

3. When $x = 6$: $y = \frac{1 - 6}{2} = \frac{-5}{2} = -2.5$ (This value is also given as -2.5.)

So the table is complete with the correct values. To graph the equation, you can plot these points:

• $(0, 0.5)$
• $(1, 0)$
• $(6, -2.5)$

The graph will be a straight line passing through these points since it's a linear equation.

Do you have any questions or want more details about the graphing process?

Here are some related questions:

1. What is the slope of the line represented by the equation $x + 2y = 1$?
2. How do you find the x-intercept and y-intercept of a linear equation?
3. How can you convert a general linear equation into slope-intercept form?
4. What are the different ways to graph a linear equation without using a table of values?
5. How does changing the coefficient of $y$ in the equation affect the graph's slope?

Tip: When graphing linear equations, it helps to find both intercepts (x and y) first. This gives you two easy points to start the graph.