The given equation is:

\[
x - 2y + 2 = 0
\]

Let's solve this for \(y\) in terms of \(x\).

### Step 1: Isolate the \(x\) term.
Move the \(x\) to the other side:

\[
-2y + 2 = -x
\]

### Step 2: Subtract 2 from both sides.
\[
-2y = -x - 2
\]

### Step 3: Divide by \(-2\) to solve for \(y\).
\[
y = \frac{-x - 2}{-2}
\]

Simplify:
\[
y = \frac{x + 2}{2}
\]

Thus, the equation in terms of \(y\) is:
\[
y = \frac{x + 2}{2}
\]

Would you like more details or have any questions?

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Here are five related questions to consider:
1. What is the slope and intercept of the line \( y = \frac{x + 2}{2} \)?
2. How would you graph this equation on the Cartesian plane?
3. Can you express this line in point-slope form?
4. How would the equation change if you doubled all the coefficients?
5. What happens if the constant term in the original equation is altered?

**Tip:** When isolating variables, always aim to simplify terms as much as possible to avoid errors.

Learn how to solve the linear equation x - 2y + 2 = 0 with a step-by-step breakdown. Understand key concepts like solving for y in terms of x and rewriting the equation in slope-intercept form, suitable for Grades 7-9.

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