The equation of a line in slope-intercept form is:

$y = mx + b$

where:

• $m$ is the slope
• $b$ is the $y$-intercept.

From the problem:

• The slope ($m$) is given as $4$,
• The $y$-intercept ($b$) is given as $1$.

Substituting these values into the equation:

$y = 4x + 1$

Thus:

• $m = 4$,
• $b = 1$.

Let me know if you'd like more details or if you have any other questions!

Related Questions

1. How would the equation change if the slope were negative?
2. Can you explain how to find the slope if only two points on the line are given?
3. What happens to the graph of this equation if $b$ changes to a negative value?
4. How would you rewrite this equation in standard form $Ax + By = C$?
5. What are the practical applications of understanding slope-intercept form?

Tip

Remember, the slope $m$ determines the steepness and direction of the line, while the $y$-intercept $b$ shows where the line crosses the $y$-axis.