The number of peas on Tarik's plate, 21, is 16 greater than the number on Raymond's plate. How many peas are on Raymond's plate?

Let the number of peas on Raymond's plate be \( x \).

According to the problem, the number of peas on Tarik's plate is 16 greater than the number on Raymond's plate. So, we have the equation:

\[
21 = x + 16
\]

To solve for \( x \), subtract 16 from both sides:

\[
x = 21 - 16
\]

\[
x = 5
\]

Thus, there are 5 peas on Raymond's plate.

Would you like more details or have any questions?

Here are 5 related questions:
1. What if Tarik had 25 peas instead? How many would Raymond have?
2. If Tarik had twice the peas as Raymond, how many peas would Raymond have?
3. How would the solution change if the difference was 10 instead of 16?
4. What if the total number of peas on both plates was 50? How many peas would each have?
5. Can you express the number of peas on Tarik’s plate as a function of Raymond's peas?

**Tip:** When solving problems involving a "greater than" or "less than" relationship, set up an equation that reflects this comparison.

Learn how to solve a basic linear equation where the number of peas on Tarik's plate is 16 more than Raymond's. This problem introduces algebraic thinking and is suitable for Grades 5-6. Follow the step-by-step process to find out how many peas Raymond has.

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