Math Problem Statement

The admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day, $5,050 is collected. If 1,000 adults attended the fair, write and solve a linear equation to find the number of children that attended. Ax+By=C

Solution

Let's define the variables as follows:

  • Let xx represent the number of children who attended the fair.
  • The number of adults who attended is given as 1,000.

We know that:

  • The admission fee for children is $1.50, so the total amount collected from children is 1.50x1.50x.
  • The admission fee for adults is $4.00, and the total amount collected from 1,000 adults is 4.00×1000=40004.00 \times 1000 = 4000.

The total amount collected from both children and adults is $5,050. Therefore, we can write the equation: 1.50x+4000=50501.50x + 4000 = 5050

Solving the equation:

  1. Subtract 4000 from both sides: 1.50x=505040001.50x = 5050 - 4000 1.50x=10501.50x = 1050

  2. Divide both sides by 1.50: x=10501.50x = \frac{1050}{1.50} x=700x = 700

Thus, 700 children attended the fair.

The linear equation is:

1.50x+4×1000=50501.50x + 4 \times 1000 = 5050

Would you like more details or have any questions?


Here are 5 related questions you can explore:

  1. What if 1,200 adults attended the fair? How would the equation change?
  2. How much would the total collection be if the admission fees were increased by 20%?
  3. How many adults and children attended if the total collected was $6,000?
  4. What if children were charged $2.00 per ticket? How many children would have attended then?
  5. How would the number of children change if fewer adults attended the fair?

Tip: When solving linear equations, it's often helpful to first isolate the variable by eliminating constants and coefficients through basic operations like addition, subtraction, multiplication, or division.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Algebra

Formulas

1.50x + 4(1000) = 5050

Theorems

Basic Algebraic Manipulation

Suitable Grade Level

Grades 6-8