https://file.aiquickdraw.com/mathbot/file/1729644510412xh6aefer.jpg

The problem in the image provides the equation $ C = 680 + 23g $, where:

- $ C $ is the cost in dollars,
- $ g $ is the number of guests.

You are asked to find the cost when the number of guests is 40. 

Let's substitute $ g = 40 $ into the equation:

\[
C = 680 + 23 \times 40
\]

First, calculate $ 23 \times 40 $:

\[
23 \times 40 = 920
\]

Now add that to 680:

\[
C = 680 + 920 = 1600
\]

So, the cost for 40 guests is **$1600**.

Would you like more details on this? Here are a few related questions to consider:

1. What does the coefficient of 23 represent in the equation?
2. How would the cost change if the number of guests was doubled?
3. If the budget was limited to $2000, how many guests could be invited?
4. How would the equation change if there was a fixed discount for large groups?
5. What is the minimum cost of the banquet if no guests attend?

**Tip:** Linear equations like this one model situations with a constant rate of change—each additional guest adds the same amount to the total cost.

An influencer is planning a lunch banquet. The equation C = 680 + 23g models the relation between the cost in dollars, C, of the lunch banquet and the number of guests, g. Find the cost if the number of guests is 40.

Learn how to calculate the cost of a banquet with 40 guests using the linear equation C = 680 + 23g. This problem covers basic algebra and linear functions. Suitable for Grades 7-9.

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