Math Problem Statement

Suppose that you stand at the point (2,3,0) and look in the direction of a point that is not visible because it is behind the ball. You will then be looking at a point on the sphere.

If (−4,−5,3) is not visible from (2,3,0), find the point on the sphere at which you are looking if you look in the direction of (−4,−5,3). Otherwise, find the point on the sphere at which you look if you are looking in the direction of (−4,−5,2). Point (x,y,z)? The equation of sphere is x²+y²+z²=sqrt(13) ,please give answer round off to 5 d.p.

Solution

We are tasked with finding the point on the surface of a sphere that you are looking at, given that you are standing at the point P0=(2,3,0)P_0 = (2, 3, 0) and looking in the direction of another point.

Key Information:

  • The sphere has an equation x2+y2+z2=13x^2 + y^2 + z^2 = \sqrt{13}.
  • The given point is either (4,5,3)(-4, -5, 3) (if not visible, the direction changes to (4,5,2)(-4, -5, 2)).

Let’s break it down.

Equation of Sphere

The equation given for the sphere seems incorrect as it is not a typical sphere equation. Assuming it was meant to be x2+y2+z2=13x^2 + y^2 + z^2 = 13 (standard form of a sphere, where 1313 is the square of the radius, which is 13\sqrt{13}).

Parametric Line Equation

The direction of the line you are looking in, from P0P_0, can be described parametrically as:

r(t)=(2,3,0)+t((42),(53),(30))\mathbf{r}(t) = (2, 3, 0) + t((-4 - 2), (-5 - 3), (3 - 0))

This simplifies to:

r(t)=(2,3,0)+t(6,8,3)\mathbf{r}(t) = (2, 3, 0) + t(-6, -8, 3)

Thus, the parametric equation for the line is:

r(t)=(26t,38t,3t)\mathbf{r}(t) = (2 - 6t, 3 - 8t, 3t)

Intersection with the Sphere

Substitute x=26tx = 2 - 6t, y=38ty = 3 - 8t, and z=3tz = 3t into the sphere equation x2+y2+z2=13x^2 + y^2 + z^2 = 13:

(26t)2+(38t)2+(3t)2=13(2 - 6t)^2 + (3 - 8t)^2 + (3t)^2 = 13

Now, expand and simplify:

(424t+36t2)+(948t+64t2)+9t2=13(4 - 24t + 36t^2) + (9 - 48t + 64t^2) + 9t^2 = 13 4+9+36t2+64t2+9t224t48t=134 + 9 + 36t^2 + 64t^2 + 9t^2 - 24t - 48t = 13 13+109t272t=1313 + 109t^2 - 72t = 13 109t272t=0109t^2 - 72t = 0 t(109t72)=0t(109t - 72) = 0

So, t=0t = 0 or t=72109t = \frac{72}{109}.

  • t=0t = 0 gives the point (2,3,0)(2, 3, 0), which is the starting point.
  • t=72109t = \frac{72}{109} gives the point on the sphere.

Coordinates of the Intersection Point

Substitute t=72109t = \frac{72}{109} into the parametric line equations:

x=26×72109=2432109=218432109=2141091.96330x = 2 - 6 \times \frac{72}{109} = 2 - \frac{432}{109} = \frac{218 - 432}{109} = \frac{-214}{109} \approx -1.96330 y=38×72109=3576109=327576109=2491092.28440y = 3 - 8 \times \frac{72}{109} = 3 - \frac{576}{109} = \frac{327 - 576}{109} = \frac{-249}{109} \approx -2.28440 z=3×72109=2161091.98165z = 3 \times \frac{72}{109} = \frac{216}{109} \approx 1.98165

Final Answer

The point on the sphere where you are looking is approximately (1.96330,2.28440,1.98165)(-1.96330, -2.28440, 1.98165).


Would you like further details or have any questions? Here are 5 follow-up questions related to this problem:

  1. How is the parametric equation of a line derived in general?
  2. What happens when you plug different values of tt into the parametric equation?
  3. What are some applications of finding intersection points with spheres?
  4. How would the process change if the sphere had a different radius?
  5. Can this method be used for other conic sections, like ellipses?

Tip: Always verify the form of a given equation before starting, as errors can propagate through calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Parametric Equations
Quadratic Equations

Formulas

Sphere equation: x² + y² + z² = r²
Parametric equation of a line: P(t) = P0 + t(P1 - P0)
Quadratic equation ax² + bx + c = 0

Theorems

Pythagorean Theorem
Quadratic Formula

Suitable Grade Level

Undergraduate level