Let's evaluate the limit:

$\lim_{x \to 0} x \csc x.$

Recall that $\csc x = \frac{1}{\sin x}$, so the expression can be rewritten as:

$\lim_{x \to 0} x \csc x = \lim_{x \to 0} \frac{x}{\sin x}.$

We know from a standard trigonometric limit that:

$\lim_{x \to 0} \frac{x}{\sin x} = 1.$

Therefore, the limit