Math Problem Statement

help me solve without giving me the answer: lim x → 0 sin(x) /2x

Solution

To solve the limit

limx0sin(x)2x,\lim_{{x \to 0}} \frac{{\sin(x)}}{{2x}},

let’s break it down step by step:

  1. Recognize the limit of the basic sine function: You might already know the standard limit result:

limx0sin(x)x=1.\lim_{{x \to 0}} \frac{{\sin(x)}}{{x}} = 1.

This fact will help simplify the problem.

  1. Rearrange the expression: Try rewriting the given limit to make use of this standard limit. You can manipulate the expression by splitting it:

sin(x)2x=12sin(x)x.\frac{{\sin(x)}}{{2x}} = \frac{1}{2} \cdot \frac{{\sin(x)}}{{x}}.

  1. Apply the limit to each part: Now, think about the limit of the product. Since the limit of sin(x)x\frac{{\sin(x)}}{{x}} as x0x \to 0 is 1, you can compute the limit of the whole expression.

Do you want to dive deeper into any of these steps or explore the justification behind the limit of sin(x)x\frac{{\sin(x)}}{{x}}?

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Math Problem Analysis

Mathematical Concepts

Limits
Trigonometric Functions
Sine Function

Formulas

lim(x→0) sin(x)/x = 1

Theorems

Limit of the sine function as x approaches 0

Suitable Grade Level

Grades 11-12