Math Problem Statement

Resuelvelosin usar lopital

Resuelve el límite sin usar L'Hôpital.

Solution

To solve the limit without using L'Hôpital's Rule, let’s analyze the behavior of the function as x0x \to 0 for the expression:

limx04x68x4+10x3+2x25x5+3x3+10x\lim_{{x \to 0}} \frac{4x^6 - 8x^4 + 10x^3 + 2x^2}{5x^5 + 3x^3 + 10x}

Step-by-Step Solution:

  1. Identify the Dominant Terms: Since we are approaching x=0x = 0, we should focus on the terms with the smallest powers of xx because they will dictate the behavior of the function near zero. Let's break down both the numerator and the denominator separately:

    • Numerator: 4x68x4+10x3+2x24x^6 - 8x^4 + 10x^3 + 2x^2
    • Denominator: 5x5+3x3+10x5x^5 + 3x^3 + 10x
  2. Divide by the Smallest Power in the Denominator ( xx ): To simplify, divide both the numerator and the denominator by xx, which is the smallest power of xx in the denominator.

    =limx04x6x8x4x+10x3x+2x2x5x5x+3x3x+10xx= \lim_{{x \to 0}} \frac{\frac{4x^6}{x} - \frac{8x^4}{x} + \frac{10x^3}{x} + \frac{2x^2}{x}}{\frac{5x^5}{x} + \frac{3x^3}{x} + \frac{10x}{x}}

    Simplify each term:

    • Numerator: 4x6x=4x5\frac{4x^6}{x} = 4x^5, 8x4x=8x3\frac{-8x^4}{x} = -8x^3, 10x3x=10x2\frac{10x^3}{x} = 10x^2, and 2x2x=2x\frac{2x^2}{x} = 2x.
    • Denominator: 5x5x=5x4\frac{5x^5}{x} = 5x^4, 3x3x=3x2\frac{3x^3}{x} = 3x^2, and 10xx=10\frac{10x}{x} = 10.

    Thus, we have:

    =limx04x58x3+10x2+2x5x4+3x2+10= \lim_{{x \to 0}} \frac{4x^5 - 8x^3 + 10x^2 + 2x}{5x^4 + 3x^2 + 10}

  3. Evaluate the Limit by Substituting x=0x = 0: Now, as x0x \to 0, all terms containing xx in the numerator and the denominator will approach zero. This leaves us with:

    =010=0= \frac{0}{10} = 0

Final Answer:

limx04x68x4+10x3+2x25x5+3x3+10x=0\lim_{{x \to 0}} \frac{4x^6 - 8x^4 + 10x^3 + 2x^2}{5x^5 + 3x^3 + 10x} = 0

Would you like more details on any part of this solution?


Related Questions:

  1. How would the solution change if we had to use L'Hôpital's Rule?
  2. What if we were approaching a different limit, such as xx \to \infty?
  3. Can we generalize this method for limits approaching zero in other rational functions?
  4. How can we factor polynomials to further simplify limits without L'Hôpital's Rule?
  5. What would happen if the numerator and denominator had the same lowest power of xx?

Tip:

When evaluating limits as x0x \to 0, look for the terms with the smallest powers in the denominator, as these will often dictate the limit's behavior.

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Math Problem Analysis

Mathematical Concepts

Limits
Polynomial Division
Limit Evaluation Techniques

Formulas

Limit of a rational function as x approaches 0

Theorems

Limit properties without using L'Hôpital's Rule

Suitable Grade Level

Grades 11-12