Math Problem Statement

𝑛→+∞ (︁4^βˆšπ‘›^4 + 2𝑛^3 - 4^βˆšπ‘›^4 + 𝑛^3)︁

Solution

Let's analyze the given expression as nβ†’+∞n \to +\infty:

lim⁑nβ†’+∞(4n4+2n3βˆ’4n4+n3)\lim_{n \to +\infty} \left( 4^{\sqrt{n^4}} + 2n^3 - 4^{\sqrt{n^4}} + n^3 \right)

First, simplify the expression 4n44^{\sqrt{n^4}}.

Step 1: Simplify 4n44^{\sqrt{n^4}}

Recall that:

n4=n2\sqrt{n^4} = n^2

Thus,

4n4=4n24^{\sqrt{n^4}} = 4^{n^2}

Step 2: Substitute into the expression

Now substitute 4n24^{n^2} into the original expression:

lim⁑nβ†’+∞(4n2+2n3βˆ’4n2+n3)\lim_{n \to +\infty} \left( 4^{n^2} + 2n^3 - 4^{n^2} + n^3 \right)

This simplifies to:

lim⁑nβ†’+∞(2n3+n3)\lim_{n \to +\infty} \left( 2n^3 + n^3 \right)

Step 3: Combine like terms

Now, add the terms 2n3+n32n^3 + n^3:

lim⁑nβ†’+∞3n3\lim_{n \to +\infty} 3n^3

Step 4: Evaluate the limit

As nβ†’+∞n \to +\infty, 3n3β†’+∞3n^3 \to +\infty. Thus, the final result is:

+∞\boxed{+\infty}

Would you like more details or have any questions?

Here are some related questions you might find helpful:

  1. How do limits behave for different powers of nn?
  2. Why does 4n24^{n^2} cancel out in the expression?
  3. What are common forms of infinity in limits?
  4. How does n3n^3 compare with higher-order terms like 4n24^{n^2}?
  5. How would the result change if the powers of nn were different?

Tip: When dealing with limits at infinity, focus on the terms with the largest growth rate, as they often dominate the result.

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Math Problem Analysis

Mathematical Concepts

Limits
Exponential Growth
Polynomials

Formulas

lim_{n β†’ +∞} (4^√(n^4) + 2n^3 - 4^√(n^4) + n^3)
4^{√(n^4)} = 4^{n^2}
lim_{n β†’ +∞} (2n^3 + n^3) = 3n^3

Theorems

Limit of polynomial functions as n approaches infinity
Growth rates of functions (polynomials vs exponentials)

Suitable Grade Level

College-level Calculus