Let's solve the limit problem provided in the image:

We are asked to compute the following limit:

$\lim_{{x \to 1}} (x^2 + 3x - 4)$

Step-by-step solution:

1. Substitute the value of $x = 1$ into the function: Since this is a polynomial, and polynomials are continuous, we can directly substitute $x = 1$ into the expression $x^2 + 3x - 4$.

   Substituting $x = 1$:

   $1^2 + 3(1) - 4 = 1 + 3 - 4 = 0$

2. Conclusion: The limit evaluates to $0$.

Thus, the final answer is:

$\lim_{{x \to 1}} (x^2 + 3x - 4) = 0$

Would you like further clarification on any of these steps?

Here are 5 related questions for practice:

1. What is $\lim_{{x \to 2}} (x^2 + 3x - 4)$?
2. How would you solve $\lim_{{x \to 1}} (2x^2 - 5x + 3)$?
3. What is the limit of $\lim_{{x \to -1}} (x^2 + 3x - 4)$?
4. Can you evaluate $\lim_{{x \to 1}} \frac{x^2 + 3x - 4}{x - 1}$?
5. How does the substitution method work for other types of functions, such as rational or trigonometric functions?

Tip: For polynomial functions, direct substitution is a valid and effective method for finding limits, since polynomials are continuous over all real numbers.