Math Problem Statement
answer all of the questions below limx->-2-f(x) limx->-2+f(x) f(-2) limx->-2f(x) limx->1-f(x) limx->1+f(x) F(1) answer all
Solution
To answer the provided limit and function evaluation questions, let's carefully analyze the graph:
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: This asks for the limit of the function as approaches from the left-hand side. Looking at the graph near from the left, we see the function approaching a value of 3.
- Answer: .
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: This asks for the limit of the function as approaches from the right-hand side. From the right side of , the function approaches a value of 2.
- Answer: .
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: The function value at is represented by a filled circle on the graph at the point , meaning .
- Answer: .
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: Since the left-hand limit () and the right-hand limit () are not equal, the overall limit does not exist.
- Answer: does not exist.
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: As approaches 1 from the left-hand side, the graph approaches a value of -4.
- Answer: .
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: As approaches 1 from the right-hand side, the graph approaches a value of 4.
- Answer: .
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: The value of the function at is indicated by an open circle at , meaning the function is not defined at .
- Answer: is undefined.
Summary of Answers:
- does not exist
- is undefined
Would you like any of these points explained further?
Here are 5 related questions for deeper exploration:
- What happens to the limit when the left and right limits are equal?
- How can we determine if a function is continuous at a certain point based on limits?
- What would be the behavior of the function if it had a filled circle at ?
- Can you have a function that is defined at but the limit at does not exist?
- How would you describe the overall continuity of this graph?
Tip:
A limit exists at a point only if both the left-hand and right-hand limits are equal at that point.
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Math Problem Analysis
Mathematical Concepts
Limits
Piecewise Functions
Continuity
Formulas
Limit of a function as x approaches a value
Continuity criteria: lim(x -> a) f(x) = f(a)
Theorems
Left-hand limit
Right-hand limit
Existence of limits
Suitable Grade Level
Grades 11-12 (Precalculus/Calculus)