The image shows a mathematical expression written in Russian. The expression appears to represent a limit:

$\lim_{x \to 4} \frac{x - 4}{x^2 - 2x - 8}$

To solve this, let's first simplify the denominator:

$x^2 - 2x - 8 = (x - 4)(x + 2)$

So, the original expression becomes:

$\lim_{x \to 4} \frac{x - 4}{(x - 4)(x + 2)}$

We can cancel the $(x - 4)$ terms (provided $x \neq 4$):

$\lim_{x \to 4} \frac{1}{x + 2}$

Now, we substitute $x = 4$ into the simplified expression:

$\frac{1}{4 + 2} = \frac{1}{6}$

Thus, the limit is:

$\frac{1}{6}$

If you would like more details or have additional questions, feel free to ask!

Here are some related questions for you:

1. What is the concept of a limit in calculus?
2. How does factoring help in simplifying rational functions?
3. Can limits be calculated when the denominator has a zero factor?
4. What are some applications of limits in real-world problems?
5. What is the significance of L'Hôpital's Rule in limit calculations?

Tip: When simplifying rational expressions, always look for common factors that can be canceled to avoid indeterminate forms.