Math Problem Statement

Evaluate the following limit: lim (3x + 4) as x -> 2. If ε = 0.1, what should we take δ to be so that |f(x) - L| < 0.1?

Solution

The image contains two math problems involving limits. Let me go through them one by one.

  1. First Problem:

    The first question asks you to evaluate the limit:

    limx2(3x+4)\lim_{{x \to 2}} (3x + 4)

    This is a basic limit problem. Since the function 3x+43x + 4 is a linear and continuous function, you can directly substitute x=2x = 2 into the expression to find the limit:

    3(2)+4=6+4=103(2) + 4 = 6 + 4 = 10

    So, the solution to the first problem is:

    limx2(3x+4)=10\lim_{{x \to 2}} (3x + 4) = 10

  2. Second Problem:

    The second part involves a question related to the epsilon-delta definition of a limit:

    It asks, "If ε=0.1\varepsilon = 0.1, what should we take δ\delta to be so that f(x)L<0.1|f(x) - L| < 0.1?"

    Here, f(x)=3x+4f(x) = 3x + 4, and from the previous problem, we know that the limit L=10L = 10.

    Using the epsilon-delta definition of a limit, we need to find a δ\delta such that whenever 0<x2<δ0 < |x - 2| < \delta, we ensure that f(x)L=(3x+4)10<0.1|f(x) - L| = |(3x + 4) - 10| < 0.1.

    Simplifying the expression f(x)L|f(x) - L|:

    (3x+4)10=3x6=3x2|(3x + 4) - 10| = |3x - 6| = 3|x - 2|

    We need this to be less than 0.1:

    3x2<0.13|x - 2| < 0.1

    Dividing both sides by 3:

    x2<0.13=0.0333|x - 2| < \frac{0.1}{3} = 0.0333\ldots

    So, δ=0.0333\delta = 0.0333 would satisfy the condition for ε=0.1\varepsilon = 0.1.


Would you like further clarification on the epsilon-delta process or any other details?

Here are 5 related questions to explore further:

  1. What is the epsilon-delta definition of a limit?
  2. How would you determine δ\delta for a different value of ε\varepsilon, say ε=0.01\varepsilon = 0.01?
  3. What does it mean for a function to be continuous at a point?
  4. How do you handle limits involving more complex functions (e.g., quadratic or trigonometric)?
  5. What is the significance of limits in calculus?

Tip: For linear functions like f(x)=3x+4f(x) = 3x + 4, the epsilon-delta process is straightforward because of the constant slope.

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Math Problem Analysis

Mathematical Concepts

Limits
Epsilon-Delta Definition
Linear Functions

Formulas

lim (3x + 4) as x -> 2 = 3(2) + 4 = 10
|(3x + 4) - 10| = 3|x - 2| < ε
ε = 0.1, δ = ε / 3

Theorems

Epsilon-Delta Definition of a Limit

Suitable Grade Level

Grades 11-12 (Calculus Level)