Math Problem Statement

Complete the table. (Round your answers to five decimal places. Assume x is in terms of radian.) lim x→0 3 sin(x) x x −0.1 −0.01 −0.001 0 0.001 0.01 0.1 f(x) 2.99500

Correct: Your answer is correct. 2.99983

Incorrect: Your answer is incorrect. 2.99998

Incorrect: Your answer is incorrect. ? 2.99998

Incorrect: Your answer is incorrect. 2.99983

Incorrect: Your answer is incorrect. 2.99500

Correct: Your answer is correct. Use the result to estimate the limit. Use a graphing utility to graph the function to confirm your result. (Round your answer to five decimal places.) lim x→0 3 sin(x) x ≈ 3.00000

Correct: Your answer is correct.

Solution

Let's break this down and complete the table step by step for the function f(x)=3sin(x)xf(x) = \frac{3 \sin(x)}{x}.

Steps:

  1. Understand the Limit Expression: limx03sin(x)x\lim_{x \to 0} \frac{3 \sin(x)}{x} This limit is very similar to the standard limit: limx0sin(x)x=1\lim_{x \to 0} \frac{\sin(x)}{x} = 1 By multiplying by 3, we expect the limit of 3sin(x)x\frac{3 \sin(x)}{x} as x0x \to 0 to be 3.

  2. Values of f(x)f(x) at Specific Points: Now, we can compute f(x)f(x) at the given xx values. For each xx, use the formula: f(x)=3sin(x)xf(x) = \frac{3 \sin(x)}{x}

    • For x=0.1x = -0.1, we know f(x)=2.99500f(x) = 2.99500 (already provided).
    • For x=0.01x = -0.01, the correct value was not given, so we'll recompute it.
    • For x=0.001x = -0.001, recompute the correct value.
    • For x=0x = 0, we know from the limit calculation that f(0)=3f(0) = 3 (since the limit approaches 3).
    • For x=0.001x = 0.001, recompute the correct value.
    • For x=0.01x = 0.01, recompute the correct value.
    • For x=0.1x = 0.1, we know f(x)=2.99500f(x) = 2.99500 (already provided).
  3. Compute the Missing Values:

I'll calculate these values for you now.Here are the calculated values for f(x)=3sin(x)xf(x) = \frac{3 \sin(x)}{x} at the given xx-values:

xxf(x)f(x)
-0.12.99500
-0.012.99995
-0.0012.99999
0 (limit)3.00000 (as x0x \to 0)
0.0012.99999
0.012.99995
0.12.99500

Conclusion:

The table is now complete, and the limit as x0x \to 0 for 3sin(x)x\frac{3 \sin(x)}{x} is 3.000003.00000.

Tip:

Whenever dealing with limits involving sin(x)\sin(x) as x0x \to 0, it's helpful to remember that limx0sin(x)x=1\lim_{x \to 0} \frac{\sin(x)}{x} = 1.

Would you like more details or clarifications on this? Here are 5 related questions to explore:

  1. What is the limit of sin(x)x\frac{\sin(x)}{x} when xx approaches infinity?
  2. How do we derive the standard limit limx0sin(x)x=1\lim_{x \to 0} \frac{\sin(x)}{x} = 1?
  3. What happens to the function 3sin(x)x\frac{3 \sin(x)}{x} for very large values of xx?
  4. Can L'Hopital's rule be applied to this problem? How?
  5. How would the table look if the function was 2sin(x)x\frac{2 \sin(x)}{x} instead of 3sin(x)3 \sin(x)?

Tip: For small angles, sin(x)x\sin(x) \approx x, which simplifies the limit calculations.

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Math Problem Analysis

Mathematical Concepts

Limits
Trigonometry
Calculus

Formulas

lim (x→0) (sin(x)/x) = 1
f(x) = 3sin(x)/x

Theorems

Squeeze Theorem
Limit Properties

Suitable Grade Level

Grade 11-12 (Calculus)