Math Problem Statement

find the least positive value of x for which cos((x/2)+(pi/3)=1/(root 2)

Solution

To find the least positive value of xx for which

cos(x2+π3)=12\cos\left(\frac{x}{2} + \frac{\pi}{3}\right) = \frac{1}{\sqrt{2}}

we'll proceed with the following steps.

Step 1: Set up the Equation

We know that:

cos(x2+π3)=12\cos\left(\frac{x}{2} + \frac{\pi}{3}\right) = \frac{1}{\sqrt{2}}

The angle for which cos(θ)=12\cos(\theta) = \frac{1}{\sqrt{2}} is θ=π4\theta = \frac{\pi}{4} and θ=7π4\theta = \frac{7\pi}{4} (or in general, θ=π4+2nπ\theta = \frac{\pi}{4} + 2n\pi or θ=7π4+2nπ\theta = \frac{7\pi}{4} + 2n\pi for integer nn).

Step 2: Set Up Possible Equations for x2+π3\frac{x}{2} + \frac{\pi}{3}

Using the values of θ\theta that satisfy the equation, we have:

  1. x2+π3=π4+2nπ\frac{x}{2} + \frac{\pi}{3} = \frac{\pi}{4} + 2n\pi
  2. x2+π3=7π4+2nπ\frac{x}{2} + \frac{\pi}{3} = \frac{7\pi}{4} + 2n\pi

where nn is an integer.

Step 3: Solve for xx

Let's solve each case for xx to find the least positive solution.

Case 1: x2+π3=π4\frac{x}{2} + \frac{\pi}{3} = \frac{\pi}{4}

  1. Subtract π3\frac{\pi}{3} from both sides: x2=π4π3\frac{x}{2} = \frac{\pi}{4} - \frac{\pi}{3}

  2. Find a common denominator and simplify: π4π3=3π4π12=π12\frac{\pi}{4} - \frac{\pi}{3} = \frac{3\pi - 4\pi}{12} = -\frac{\pi}{12}

  3. Multiply by 2 to solve for xx: x=π6x = -\frac{\pi}{6}

Since we are looking for the least positive xx, this solution is not applicable here.

Case 2: x2+π3=7π4\frac{x}{2} + \frac{\pi}{3} = \frac{7\pi}{4}

  1. Subtract π3\frac{\pi}{3} from both sides: x2=7π4π3\frac{x}{2} = \frac{7\pi}{4} - \frac{\pi}{3}

  2. Simplify by finding a common denominator: 7π4π3=21π4π12=17π12\frac{7\pi}{4} - \frac{\pi}{3} = \frac{21\pi - 4\pi}{12} = \frac{17\pi}{12}

  3. Multiply by 2 to solve for xx: x=17π6x = \frac{17\pi}{6}

Conclusion

The least positive value of xx that satisfies the equation is:

x=17π6x = \frac{17\pi}{6}

Would you like a more detailed explanation of any step, or have any other questions?


Here are some related questions to expand on this topic:

  1. What other trigonometric functions have periodic solutions, and how do we find them?
  2. How do we solve equations involving both sine and cosine functions?
  3. How can we determine all possible solutions in a given interval?
  4. What are some practical applications of trigonometric equations in physics or engineering?
  5. How can we use inverse trigonometric functions to solve similar equations?

Tip: For trigonometric equations, using known values and symmetries of the trigonometric functions often helps simplify and solve complex expressions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Equations
Cosine Function
Angle Identities

Formulas

cos(θ) = 1/√2 at θ = π/4, 7π/4
General form of cosine solutions: θ = π/4 + 2nπ or θ = 7π/4 + 2nπ

Theorems

Cosine function periodicity and symmetry

Suitable Grade Level

Grades 10-12