Math Problem Statement

Ikkita o'zaro tub sonlarning EKUKi 108 ga teng bo'lsa, bu sonlarning ko'paytmasini toping. 45 sonining tub bo'luvchilari nechta? Hisoblang: 1^3 + 2^3 + 3^3 + 4^3 / (2 + 3)^2. a = 2^3 . 3^2 . 5; b = 2^2 . 3^3 . 5^2 bo'lsa, EKUK(a,b)/EKUB(a,b) ning qiymatini toping.

Solution

Let's analyze the questions from the image and solve them step by step.

1. First Question:

  • Problem: Ikkita o'zaro tub sonlarning EKUKi 108 ga teng bo'lsa, bu sonlarning ko'paytmasini toping. (If the LCM of two co-prime numbers is 108, find their product.)

Solution: If two numbers are co-prime, their Least Common Multiple (LCM or EKUK) is simply the product of the two numbers. Therefore, if their LCM is 108, their product must also be 108.

Answer: B)108\boxed{B) 108}

2. Second Question:

  • Problem: 45 sonining tub bo'luvchilari nechta? (How many prime divisors does 45 have?)

Solution: First, find the prime factorization of 45: 45=32×545 = 3^2 \times 5 The prime divisors of 45 are 3 and 5, so there are 2 distinct prime divisors.

Answer: B)2\boxed{B) 2}

3. Third Question:

  • Problem: Hisoblang:13+23+33+43(2+3)2Hisoblang: \frac{1^3 + 2^3 + 3^3 + 4^3}{(2 + 3)^2} (Calculate the given expression.)

Solution: Let's break this down: 13+23+33+43=1+8+27+64=1001^3 + 2^3 + 3^3 + 4^3 = 1 + 8 + 27 + 64 = 100 (2+3)2=52=25(2 + 3)^2 = 5^2 = 25 So, the expression becomes: 10025=4\frac{100}{25} = 4

Answer: C)4\boxed{C) 4}

4. Fourth Question:

  • Problem: Given a=23×32×5a = 2^3 \times 3^2 \times 5 and b=22×33×52b = 2^2 \times 3^3 \times 5^2, find EKUK(a,b)EKUB(a,b)\frac{EKUK(a, b)}{EKUB(a, b)}.

Solution:

  • EKUK (LCM) is found by taking the highest powers of all prime factors: EKUK(a,b)=23×33×52EKUK(a, b) = 2^3 \times 3^3 \times 5^2
  • EKUB (GCD) is found by taking the lowest powers of all prime factors: EKUB(a,b)=22×32×5EKUB(a, b) = 2^2 \times 3^2 \times 5 Now, calculate: EKUK(a,b)EKUB(a,b)=23×33×5222×32×5=232×332×521=2×3×5=30\frac{EKUK(a, b)}{EKUB(a, b)} = \frac{2^3 \times 3^3 \times 5^2}{2^2 \times 3^2 \times 5} = 2^{3-2} \times 3^{3-2} \times 5^{2-1} = 2 \times 3 \times 5 = 30

Answer: B)30\boxed{B) 30}

Would you like more details on any of these solutions, or do you have other questions?

Here are 5 related questions to practice:

  1. If two numbers are co-prime and their product is 72, what is their LCM?
  2. What are the prime divisors of 60?
  3. Calculate the sum of cubes from 131^3 to 535^3.
  4. Given a=24×3×7a = 2^4 \times 3 \times 7 and b=22×33×72b = 2^2 \times 3^3 \times 7^2, find EKUK(a,b)EKUB(a,b)\frac{EKUK(a, b)}{EKUB(a, b)}.
  5. If two numbers have an EKUB (GCD) of 12 and an EKUK (LCM) of 360, what is their product?

Tip: Always factorize numbers into primes when solving LCM or GCD problems.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Prime Factorization
LCM (EKUK)
GCD (EKUB)
Exponents
Simplification

Formulas

LCM(a, b) = Product of highest powers of all prime factors.
GCD(a, b) = Product of lowest powers of all prime factors.
Sum of cubes: a^3 + b^3 + c^3

Theorems

LCM and GCD relationship
Prime factorization

Suitable Grade Level

Grades 9-11