Math Problem Statement

z0 is an isolated singularity of f(z) if f(z) is analytic in the punctured disk 0 < |z - z0| < r. Determine if f(z) has a Laurent series expansion in this domain.

Solution

The question asks whether z0z_0 is an isolated singularity of f(z)f(z) given that f(z)f(z) is analytic in the punctured disk 0<zz0<r0 < |z - z_0| < r, and whether this implies that f(z)f(z) has a Laurent series expansion in this domain.

In complex analysis, if f(z)f(z) is analytic in the punctured neighborhood around z0z_0, then z0z_0 is indeed an isolated singularity. Additionally, any isolated singularity allows for a Laurent series expansion of f(z)f(z) in 0<zz0<r0 < |z - z_0| < r.

Thus, the statement "has a Laurent series expansion" is correct. The answer should be:

  • B. ✅ (Correct)

Would you like further details on Laurent series, types of singularities, or how to approach similar problems?


Here are some related questions for further exploration:

  1. What are the different types of isolated singularities?
  2. How does a Laurent series differ from a Taylor series?
  3. What does it mean if the Laurent series of f(z)f(z) around z0z_0 contains a principal part?
  4. Can a singularity still be isolated if f(z)f(z) is not analytic in the punctured disk?
  5. What are the conditions for a singularity to be classified as essential?

Tip: To determine the type of singularity, analyze the terms in the Laurent series expansion around that point.

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Math Problem Analysis

Mathematical Concepts

Complex Analysis
Isolated Singularities
Laurent Series

Formulas

Laurent series expansion formula for f(z) around z0

Theorems

Laurent's Theorem

Suitable Grade Level

Undergraduate Mathematics